dictionary

Converting list of lists in dictionary python

こ雲淡風輕ζ 提交于 2021-01-28 18:48:39
问题 I'm facing the following problem. I have a list of lists obtained from a remote URL with the following code: import csv import urllib.request text_url = 'https://www.emidius.eu/fdsnws/event/1/query?starttime=1899-01-01T00:00:00&endtime=1899-01-31T23:59:59&minmag=4&maxmag=9&orderby=time-asc&limit=100&format=text' with urllib.request.urlopen(text_url) as response: my_text = response.read().decode() lines = my_text.splitlines() reader = csv.reader(lines, delimiter='|') I can convert the reader

R//ggplot2: Dynamic title when combining facet_wrap and for loop

只愿长相守 提交于 2021-01-28 16:51:17
问题 I have a spatialtemporal dataset with various indicators for a set of location that I wish to map overtime. Here is my facet_wrap + loop #basemap basemap <- ggplot() + geom_sf(data= country_adm2) + coord_sf() + theme_void() print(basemap) #joining dataframe to polygons df_poly <- left_join(country_adm2, df, by= "County") ##joins the data by County. #loop & facet_wrap plots ## This goes over the dataset (df_poly) to plot the the three variables, and facet_wrap over ~Date to see time variation

R//ggplot2: Dynamic title when combining facet_wrap and for loop

北战南征 提交于 2021-01-28 16:50:25
问题 I have a spatialtemporal dataset with various indicators for a set of location that I wish to map overtime. Here is my facet_wrap + loop #basemap basemap <- ggplot() + geom_sf(data= country_adm2) + coord_sf() + theme_void() print(basemap) #joining dataframe to polygons df_poly <- left_join(country_adm2, df, by= "County") ##joins the data by County. #loop & facet_wrap plots ## This goes over the dataset (df_poly) to plot the the three variables, and facet_wrap over ~Date to see time variation

R//ggplot2: Dynamic title when combining facet_wrap and for loop

99封情书 提交于 2021-01-28 16:45:24
问题 I have a spatialtemporal dataset with various indicators for a set of location that I wish to map overtime. Here is my facet_wrap + loop #basemap basemap <- ggplot() + geom_sf(data= country_adm2) + coord_sf() + theme_void() print(basemap) #joining dataframe to polygons df_poly <- left_join(country_adm2, df, by= "County") ##joins the data by County. #loop & facet_wrap plots ## This goes over the dataset (df_poly) to plot the the three variables, and facet_wrap over ~Date to see time variation

Merging multiple arrays into a map

谁说我不能喝 提交于 2021-01-28 14:08:30
问题 I have some data (sample from full table) that looks like this: | prov_id | hotel_id | m_id | apis_xml | company_id | yyyy_mm_dd | |---------|----------|------|----------|------------|------------| | 945 | 78888 | 3910 | [5] | 998 | 2020-05-20 | | 1475 | 78888 | 6676 | [1,2,4] | 37 | 2020-05-20 | | 1475 | 78888 | 6670 | [1,2,4] | 37 | 2020-05-20 | | 945 | 78888 | 2617 | [5] | 998 | 2020-05-20 | I want to find the lowest apis_xml value per hotel and have the associated prov_id set as the

How could I improve the speed of my algorithm, even by the slightest amount

╄→гoц情女王★ 提交于 2021-01-28 14:00:44
问题 How can I improve the speed of my algorithm, even by the slightest amount. For the reason I made this I don't actually care about speed in the slightest, but I'm wondering what I could change if I did. Even more than pointing out specific things to change, what I really want to know is how you know that there's a more efficient way and how that way works. Basically, what is the track to follow if you want to learn how the low level stuff works so that you can write better code at the higher

Find all unique pairs of keys of a dictionary

你说的曾经没有我的故事 提交于 2021-01-28 12:06:36
问题 If there's a dictionary: test_dict = { 'a':1,'b':2,'c':3,'d':4} I want to find pairs of keys in list of tuples like: [('a','b'),('a','c'),('a','d'),('b','c'),('b','d'),('c','d')] I tried with the following double iteration test_dict = { 'a':1,'b':2,'c':3,'d':4} result = [] for first_key in test_dict: for second_key in test_dict: if first_key != second_key: pair = (first_key,second_key) result.append(pair) But it's generating the following result [('a', 'c'), ('a', 'b'), ('a', 'd'), ('c', 'a')

How to add suffix to a plain text in python

情到浓时终转凉″ 提交于 2021-01-28 11:42:55
问题 I have the following text that I want to send by mail. I have to convert it to html, therefore to each line separator I have to add . How can I do it in such a way that it fits me? Here is my attempt. text = """ Hi, my name is John, Regards """ strString = map(lambda x: x + '<br>', text) print(list(strString)) ['\n<br>', 'H<br>', 'i<br>', ',<br>', ' <br>', 'm<br>', 'y<br>', ' <br>', 'n<br>', 'a<br>', 'm<br>', 'e<br>', ' <br>', 'i<br>', 's<br>', ' <br>', 'J<br>', 'o<br>', 'h<br>', 'n<br>', ',

Python: Apply a function to multiple subsets of a dataframe (stored in a dictionary)

梦想与她 提交于 2021-01-28 11:16:07
问题 Regards, Apologies if this question appears be to a duplicate of other questions. But I could find an answer that addresses my problem in its exactitude. I split a dataframe, called "data", into multiple subsets that are stored in a dictionary of dataframes named "dfs" as follows: # Partition DF dfs = {} chunk = 5 for n in range((data.shape[0] // chunk + 1)): df_temp = data.iloc[n*chunk:(n+1)*chunk] df_temp = df_temp.reset_index(drop=True) dfs[n] = df_temp Now, I would like to apply a pre

How to build an alphabetical tree from a list of words in R?

别等时光非礼了梦想. 提交于 2021-01-28 10:56:22
问题 My problem is simple. I have a long list of words, e.g. abbey, abbot, abbr, abide. I would like to build a tree as follows: Level 0 A | Level 1 B / \ Level 2 B I / | \ | Level 3 E O R D | | | Level 4 Y T E Is there an easy way to parse the wordlist and create such a structure in R? Thanks a lot for your help! Sincerely, Chris 回答1: Here's an igraph -based solution that labels each node of the graph with the partial word, so that terminal nodes are named with full words: library(igraph) library