dictionary

问题 I have a tree structure that looks something like this: interface TreeData { id : number; text : string; children : TreeData[]; } I want to wrap this up into an Immutable Map but since I'm using TypeScript, I would like some type safety around using get and set. I found 2 articles online for suggestions on how one might be able to do this, see: https://github.com/facebook/immutable-js/issues/683 https://blog.mayflower.de/6630-typescript-redux-immutablejs.html However my problem is that my

问题 Imagine a multimap tracking persons, each of whom has a list of assigned tasks. Map< Person , List< Task > > personToTasks = Map.of( new Person( "Alice" ) , List.of( new Task( "a1" ), new Task( "a2") ) , new Person( "Bob" ) , List.of( new Task( "b1" ) ) , new Person( "Carol" ) , List.of( new Task( "c1" ), new Task( "c2"), new Task( "c3") ) ) ; How can I use streams to get a new map, mapping each Person to an Integer with the count of items found in their list of assigned tasks? How to get a

问题 Imagine a multimap tracking persons, each of whom has a list of assigned tasks. Map< Person , List< Task > > personToTasks = Map.of( new Person( "Alice" ) , List.of( new Task( "a1" ), new Task( "a2") ) , new Person( "Bob" ) , List.of( new Task( "b1" ) ) , new Person( "Carol" ) , List.of( new Task( "c1" ), new Task( "c2"), new Task( "c3") ) ) ; How can I use streams to get a new map, mapping each Person to an Integer with the count of items found in their list of assigned tasks? How to get a

问题 I am currently trying to find a more pythonic way of filtering a dictionary using another dictionary. Currently I have the following code: def filter_respondents(data_dict, tolerance): NaN_dict = diagnostic_tools.get_NaN_ratio(data_dict) final_dict = {} for respondent in data_dict: if NaN_dict[respondent]<=tolerance: final_dict[respondent] = data_dict[respondent] return final_dict The code does what I want it to do but I'm looking for a better way of doing it. Basically I have 2 dictionaries.

问题 I have a column named word_count which contains the count of all the words in a review. How can I find the number of times the word awesome has occurred in each row of that column and use .apply() method to make it into a new column say awesome . products['word_count'][1] {'and': 3L,'bags': 1L,'came': 1L, 'disappointed.':1L,'does':1L,'early':1L,'highly': 1L,'holder.': 1L, 'awesome': 2L} how can i get the output products['awesome'][1] 2 回答1: What I understood from you is that you have a

问题 I have a table with misspelling words. I need to correct those using from the words more similar to that one, the one that have more frequency. For example, after I run aggregate(CustomerID ~ Province, ventas2, length) I get 1 2 AMBA 29 3 BAIRES 1 4 BENOS AIRES 1 12 BUENAS AIRES 1 17 BUENOS AIRES 4 18 buenos aires 7 19 Buenos Aires 3 20 BUENOS AIRES 11337 35 CORDOBA 2297 36 cordoba 1 38 CORDOBESA 1 39 CORRIENTES 424 So I need to replace buenos aires, Buenos Aires, Baires, BUENOS AIRES, with

问题 Is there any way to replace value using dictionary or mapping? I have dataframe like this: Q14r63: Audi Q14r2: BMW Q14r1: VW Selected Not Selected Not Selected Not Selected Selected Selected Selected Selected Not Selected and i have another dataframe which provides codes for the Brands. This df ofcourse can be changed into dictionary also. Brand Code Audi 63 BMW 2 VW 1 Is there any way to get output where "selected" values in main df can be be changes with car brand? Desired Output Q14r63:

问题 I am scrapping some listings of a website and managed to get most of the features to work except scrapping the description. here is the URL of one ad : https://eg.hatla2ee.com/en/car/honda/civic/3289785 Here is my code: for link in df['New Carlist Unit 1_link']: url = requests.get(link) soup = BeautifulSoup(url.text, 'html.parser') ### Get title title =[] try: title.append(soup.find('h1').text.strip()) except Exception as e: None ## Get price price = [] try: price.append(soup.find('span'

问题 I am scrapping some listings of a website and managed to get most of the features to work except scrapping the description. here is the URL of one ad : https://eg.hatla2ee.com/en/car/honda/civic/3289785 Here is my code: for link in df['New Carlist Unit 1_link']: url = requests.get(link) soup = BeautifulSoup(url.text, 'html.parser') ### Get title title =[] try: title.append(soup.find('h1').text.strip()) except Exception as e: None ## Get price price = [] try: price.append(soup.find('span'

问题 If one binds to a listbox's ItemsSource to a list type structure such as an ObservableCollection (or any value-only container really) with the type of a class ( List< MyClass> ) one can access the properties of said class. But if one has a Dictionary<long, MyClass> and binds the itemssource to Dictionary.Values one can not access the class properties anymore. So basically this is my XAML <ListBox ItemsSource="{Binding bm.Values}"> <ListBox.ItemTemplate> <DataTemplate> <StackPanel> <TextBlock