dictionary

问题 Given some arbitrary dictionary mydict = { 'first': { 'second': { 'third': { 'fourth': 'the end' } } } } I've written a small routine to flatten it in the process of writing an answer to another question. def recursive_flatten(mydict): d = {} for k, v in mydict.items(): if isinstance(v, dict): for k2, v2 in recursive_flatten(v).items(): d[k + '.' + k2] = v2 else: d[k] = v return d It works, giving me what I want: new_dict = recursive_flatten(mydict) print(new_dict) {'first.second.third.fourth

问题 As the title suggests I wanted to enumerate the key and its values (without brackets) in python. I tried the following code : example_dict = {'left':'<','right':'>','up':'^','down':'v',} [print(i,j,a) for (i,j,a) in enumerate(example_dict.items())] But it doesn't work. I want the output to be like this 0 left < 1 right > 2 up ^ 3 down v Thank you in advance 回答1: In this case enumerate returns (index, (key, value)) , so you just need to change your unpacking to for i, (j, a) , though

问题 I'm tryping to create a dataframe with closingprices for stocks and have found a free api that returns JSON-data in the form of nested dicts with the data, looking like this: {'name': 'AAPL', 'history': {'2019-01-04': {'open': '144.53', 'close': '148.26', 'high': '148.55', 'low': '143.80', 'volume': '58607070'}, '2019-01-03': {'open': '143.98', 'close': '142.19', 'high': '145.72', 'low': '142.00', 'volume': '91312195'}, '2019-01-02': {'open': '154.89', 'close': '157.92', 'high': '158.85',

问题 Could you assist me with replacing an identifier value with a value from a dictionary. So the code looks like follow #string holds the value we want to output s = '${1}_p${guid}s_${2}' d = {1: 'bob', 2: '123abc', 3: 'CA', 4: 'smith' } I want to be able to replace ${1} with bob and ${2} with 123abc, I only want to change a value if the value inside ${} is just a number then, replace it with the value within the dictionary. output = 'bob_p${guid}s_123abc' I tried using template module, but it

问题 I am trying to sort a dictionary, the order which I want to follow is that first, the dictionary should be sorted in increasing order by values and if the values for two or more keys are equal then I want to sort the dictionary by the keys in descending order. Here is the code: dictionary = {0: 150, 1: 151, 2: 150, 3: 101, 4: 107} print(sorted(dictionary.items(), key=lambda x: (x[1], x[0]))) I want the output to be the following: [(3, 101), (4, 107), (2, 150), (0, 150), (1, 151)] But the

问题 I wanted to know how I can find duplicate values in a dictionary and the return the keys that contain those values. So here is an example: d = {'happy':['sun', 'moon', 'chocolate'], 'sad':['fail', 'test', 'bills'], 'random': ['baloon', 'france', 'sun'] } As you can see the key's happy and random have the same/duplicate value in them, which is 'sun' , so the output I was looking for is: random, happy I cant really understand how I can find duplicate values like that. If I had a particular

问题 I have a class which contains 4 dictionaries. public class FishInformation { public int FishId { get; set; } public Dictionary<string,int> DicGroup { get; set; } public Dictionary<string, int> DicEvent { get; set; } public Dictionary<string, int> DicAudience { get; set; } public Dictionary<string, int> DicType { get; set; } } I want get the dictionary name by a string and add items to it. So this question suggests using System.Reflection to do so. this is the code I tried: FishInformation

问题 I'm looking for an 'efficient' way to iterate through a dictionary, and replace any key or value that starts with the term 'var'. For example, if I have this: data = { "user_id": "{{var_user_id}}", "name": "bob", "{{var_key_name}}": 4 } and I have this dict of variable values: variables = { "user_id": 10, "key_name": "orders_count" } Then I'd like my final data dict to look like this: data = { "user_id": 10, "name": "bob", "orders_count": 4 } 回答1: Since you're treating it like a text template

问题 I have a csv file. I want to create dictionary from this data.I should not pandas. Data looks like this: I do this. But size of the numbers is not same. How can I create a dictionary? filename=" data.dat" file=open(filename, encoding="latin-1").read().split(' , ') dictt={} for row in file: dictt[row[0]] = {‘values’, row[1]} I have a file as above. First, I need to create a dict. After that, I will print the daily number of unique measurements in desending order according to date. Final

问题 I'd like to remove the list of dictionaries elements that have empty values. So for the following: dict = [{"end": "00:15", "item": "Paul Test 1", "start": "00:00"}, {"end": "00:14", "item": "Paul Test 2 ", "start": "00:30"}, {"end": "", "item": "", "start": ""}, {"end": "", "item": "", "start": ""}, {"end": "", "item": "", "start": ""}] would return a new dict of: [{"end": "00:15", "item": "Paul Test 1", "start": "00:00"}, {"end": "00:14", "item": "Paul Test 2 ", "start": "00:30"}] I've