regex javascript to match both RGB and RGBA

青春壹個敷衍的年華 提交于 2019-12-17 16:58:48

问题


Currently I have this regex which matches to an RGB string. I need it enhanced so that it is robust enough to match either RGB or RGBA.

rgbRegex = /^rgb\((\d+),\s*(\d+),\s*(\d+)\)$/; //matches RGB

http://jsfiddle.net/YxU2m/

var rgbString =  "rgb(0, 70, 255)";
var RGBAString = "rgba(0, 70, 255, 0.5)";

var rgbRegex = /^rgb\((\d+),\s*(\d+),\s*(\d+)\)$/;
//need help on this regex
//I figure it needs to be ^rgba?, and then also an optional clause to handle the opacity

var partsRGB = rgbString.match(rgbRegex);
var partsRGBA = RGBAString.match(rgbRegex);

console.log(partsRGB); //["rgb(0, 70, 255)", "0", "70", "255"]
console.log(partsRGBA); //null. I want ["rgb(0, 70, 255, 0.5)", "0", "70", "255", "0.5"] 

回答1:


Will this do?

var rgbRegex = /^rgba?\((\d+),\s*(\d+),\s*(\d+)(?:,\s*(\d+(?:\.\d+)?))?\)$/



回答2:


It's not so simple- an rgb is illegal with a fourth parameter. You also need to allow for percentage decimals as well as integer values for the rgb numbers. And spaces are allowed almost anywhere.

function getRgbish(c){
    var i= 0, itm,
    M= c.replace(/ +/g, '').match(/(rgba?)|(\d+(\.\d+)?%?)|(\.\d+)/g);
    if(M && M.length> 3){
        while(i<3){
            itm= M[++i];
            if(itm.indexOf('%')!= -1){
                itm= Math.round(parseFloat(itm)*2.55);
            }
            else itm= parseInt(itm);
            if(itm<0 || itm> 255) return NaN;
            M[i]= itm;
        }
        if(c.indexOf('rgba')=== 0){
            if(M[4]==undefined ||M[4]<0 || M[4]> 1) return NaN;
        }
        else if(M[4]) return NaN;
        return M[0]+'('+M.slice(1).join(',')+')';
    }
    return NaN;
}

//testing:

var A= ['rgb(100,100,255)',
'rgb(100,100,255,.75)',
'rgba(100,100,255,.75)',
'rgb(100%,100%)',
'rgb(50%,100%,0)',
'rgba(100%,100%,0)',
'rgba(110%,110%,0,1)'];

A.map(getRgbish).join('\n');

returned values:
rgb(100,100,255)
NaN
rgba(100,100,255,.75)
NaN
rgb(127,255,0)
NaN
NaN



回答3:


I made a regex that checks for rgb() and rgba() values. It checks for 3 tuples of 0-255 and then an optional decimal number between 0-1 for transparency. TLDR;

rgba?\(((25[0-5]|2[0-4]\d|1\d{1,2}|\d\d?)\s*,\s*?){2}(25[0-5]|2[0-4]\d|1\d{1,2}|\d\d?)\s*,?\s*([01]\.?\d*?)?\)

Broken into the different parts we have:

rgba?\( // Match rgb( or rgba( as the a is optional

0-255 is matched with alternation of:

\d\d? // Match 0-99

1\d\d // Match 100 - 199

2[0-4]\d // Match 200-249

25[0-5] // Match 250 - 255

The handling of comma and space around the 0-255 tuples takes some space. I match 0-255 tuples with mandatory trailing comma and optional spaces twice

(25[0-5]|2[0-4]\d|1([0-9]){1,2}|\d\d?)\s*,\s*){2}

Then a 0-255 tuple with optional comma and space - to allow for rgb() values without the trailing comma

(25[0-5]|2[0-4]\d|1([0-9]){1,2}|\d\d?),?\s*

Then comes an optional 0-1 as whole number or decimal number:

([01]\.?\d*?)? // 0 or 1 needed, dot and decimal numbers optional

And we end with a closing bracket

\)



回答4:


If you need to be strict, i.e. rule out rgb(0, 70, 255, 0.5), you need to fuse both cases together with | :

var rgbRegex = /(^rgb\((\d+),\s*(\d+),\s*(\d+)\)$)|(^rgba\((\d+),\s*(\d+),\s*(\d+)(,\s*\d+\.\d+)*\)$)/; 

http://jsfiddle.net/YxU2m/2/




回答5:


i use this it is help

(.*?)(rgb|rgba)\((\d+),\s*(\d+),\s*(\d+)(?:,\s*(\d+(?:\.\d+)?))?\)/i

if you check rgba(102,51,68,0.6)

it will return

1.  [0-0]   ``
2.  [0-4]   `rgba`
3.  [5-8]   `102`
4.  [9-11]  `51`
5.  [12-14] `68`
6.  [15-18] `0.6`

and if you check rgb(102,51,68)

it will return

1.  [21-21] ``
2.  [21-24] `rgb`
3.  [25-28] `102`
4.  [29-31] `51`
5.  [32-34] `68`



回答6:


This regex is a good compromise between the complexity of the regex and number of use-cases covered.

/(rgb\(((([01]?[0-9]?[0-9]|2[0-4][0-9]|25[0-5]),\s*){2}([01]?[0-9]?[0-9]|2[0-4][0-9]|25[0-5])\)))|(rgba\(((([01]?[0-9]?[0-9]|2[0-4][0-9]|25[0-5]),\s*){3}(1|1.0*|0?.\d)\)))/

rgb and rgba need to be treated differently as one needs the 4th argument and one doesn't.

This regex takes that into account. It also deals with:

  • 1, 2 or 3 digit rgb values
  • rgb values under 0 and over 255
  • (some) spaces
  • a 4th value missing from rgba
  • a 4th value in rgb

This regex does not take into account:

  • every legal type of spacing
  • percentage based rgb values



回答7:


Try the following script for RGBA value, the result is an object.

       var getRGBA = function (string) {
          var match = string.match(/^rgba\((\d{1,3}),\s*(\d{1,3}),\s*(\d{1,3}),\s*(\d*(?:\.\d+)?)\)$/);
          return match ? {
            r: Number(match[1]),
            g: Number(match[2]),
            b: Number(match[3]),
            a: Number(match[4])
          } : {}
        };
                           
        var rgba = getRGBA('rgba(255, 255, 255, 0.49)');
        console.log(rgba);



回答8:


For patterns: rbga(12,123,12,1) rbga(12,12,12, 0.232342) rgb(2,3,4)

/^(rgba|rgb)\(\s?\d{1,3}\,\s?\d{1,3}\,\s?\d{1,3}(\,\s?(\d|\d\.\d+))?\s?\)$/


来源:https://stackoverflow.com/questions/7543818/regex-javascript-to-match-both-rgb-and-rgba

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