问题
Alright. I have implemented a custom JTable model that includes the whole
@Override
public Class<?> getColumnClass(final int column) {
and inside that I have
if (column == 0)
return Boolean.class;
When I run, and I go to the JTable, instead of a checked JCheckbox, it says true. When I click on it, it turns into a JCheckBox until I unclick and then either says true or false.
WHAT AM I DOING WRONG!!???
回答1:
really don't know, you can compare your code with
note both definitions for Column.Class are valid, you can try it that with uncomment blocked code
import java.awt.*;
import javax.swing.*;
import javax.swing.table.*;
public class TablePrepareRenderer extends JFrame {
private static final long serialVersionUID = 1L;
private JTable table;
public TablePrepareRenderer() {
Object[] columnNames = {"Type", "Company", "Shares", "Price", "Boolean"};
Object[][] data = {
{"Buy", "IBM", new Integer(1000), new Double(80.50), false},
{"Sell", "MicroSoft", new Integer(2000), new Double(6.25), true},
{"Sell", "Apple", new Integer(3000), new Double(7.35), true},
{"Buy", "Nortel", new Integer(4000), new Double(20.00), false}
};
DefaultTableModel model = new DefaultTableModel(data, columnNames);
table = new JTable(model) {
private static final long serialVersionUID = 1L;
/*@Override
public Class getColumnClass(int column) {
return getValueAt(0, column).getClass();
}*/
@Override
public Class getColumnClass(int column) {
switch (column) {
case 0:
return String.class;
case 1:
return String.class;
case 2:
return Integer.class;
case 3:
return Double.class;
default:
return Boolean.class;
}
}
@Override
public Component prepareRenderer(TableCellRenderer renderer, int row, int column) {
Component c = super.prepareRenderer(renderer, row, column);
int firstRow = 0;
int lastRow = table.getRowCount() - 1;
if (row == lastRow) {
((JComponent) c).setBackground(Color.red);
} else if (row == firstRow) {
((JComponent) c).setBackground(Color.blue);
} else {
((JComponent) c).setBackground(table.getBackground());
}
return c;
}
};
table.setPreferredScrollableViewportSize(table.getPreferredSize());
JScrollPane scrollPane = new JScrollPane(table);
getContentPane().add(scrollPane);
}
public static void main(String[] args) {
SwingUtilities.invokeLater(new Runnable() {
@Override
public void run() {
TablePrepareRenderer frame = new TablePrepareRenderer();
frame.setDefaultCloseOperation(EXIT_ON_CLOSE);
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}
});
}
}
回答2:
I ran across a similar problem while examining this (flawed) example. The method invocation getDefaultRenderer(Boolean.class) returns a JTable.BooleanEditor irrespective of the result returned by getColumnClass(), which is java.lang.Object for the unalloyed DefaultTableModel. To see the effect, drag the checkbox column to a new location and click the checkbox header. The new column zero in the view will now alternate between true and false.
回答3:
table = new JTable(model) {
private static final long serialVersionUID = 1L;
/*@Override
public Class getColumnClass(int column) {
return getValueAt(0, column).getClass();
}*/
@Override
public Class getColumnClass(int column) {
switch (column) {
case 0:
return String.class;
case 1:
return String.class;
case 2:
return Integer.class;
case 3:
return Double.class;
default:
return Boolean.class;
}
}
I got this issue solved using the answer given by MKorbel.
来源:https://stackoverflow.com/questions/7183503/how-would-i-go-about-changing-the-boolean-string-to-a-jcheckbox-in-jtable