widget

问题 Can someone tell me how to check that my widget have been placed on the homescreen? I have some code in my app that should run only if the widget is placed on the homescreen. 回答1: You need to store that information yourself. I usually use the application preferences, but you could use anything. Generally widgets use services to communicate, so your code that does stuff is likely in a service, but using the preference allows any portion of your app to access this. In your widget class that

问题 I'm looking to essentially replicate this: What is the most appropriate Qt container widget for displaying my custom widgets containing image+subscript? I'm looking at QTableView and it seems to be supposed to have a set number of rows/columns, while I would like my program to change layout depending on window width (so that there is no horizontal scroll), and adding new widget should be done with addWidget(QWidget * w) , not setWidget(int row, int column, QWidget * w) . Is there a better

问题 I have written a program that uses widgets as container (for other widgets). Because the contents of the container varies along the program life, the container widget has a layout associated to it so it resizes properly. The problem is that the container seems to consume some space. In the following program, I have reproduced the problem: I have a group with a few labels, where one of them is included in a container (the widget w -and its layout t- includes the label "what is that extra space

问题 I've built an appWidget which register some services on his onEnabled() method. The problem is that after I use the built in Task Manager's Clean Memmory/Ram, the appWidget view crashes (all the appWidgets TextView's text is set to default (TextView)) and the Services stop running and never restarts. This only happen after some time the widget is set, and if I Clean Memmory/Ram right after the widget is set the bug does'nt happen, but I guess this is related to the Task Manager's method of

问题 As it currently stands, this question is not a good fit for our Q&A format. We expect answers to be supported by facts, references, or expertise, but this question will likely solicit debate, arguments, polling, or extended discussion. If you feel that this question can be improved and possibly reopened, visit the help center for guidance. Closed 7 years ago . Does anyone know where can I find a tutorial or example on how to achive this kind of number picker dialog on android? I googled

问题 I have a widget I created against Android 2.1 that's been fine and selling on the market. I had a user complain that he bought it and it never showed up on his Android 4.0 device. I loaded up the 4.0 emulator, ran it from Eclipse, it reported a successful installation and in fact I can see it listed in the "Widget Preview" app, and I can run it there and it seems fine, but it doesn't show up anywhere under "Widgets" -- I can't actually find it to drag it to the home screen! I assume this is

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 years ago . public class FlashLightActivity extends Activity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); //setContentView(R.layout.main); Context context = this; PackageManager packageManager = context.getPackageManager(); // if device support camera? if (packageManager

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 years ago . public class FlashLightActivity extends Activity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); //setContentView(R.layout.main); Context context = this; PackageManager packageManager = context.getPackageManager(); // if device support camera? if (packageManager

问题 In my app, I need to show and hide widgets like button and textview at a certain time. and how I am doing is as the following: private void hideviews() { image.setVisibility(View.GONE); ///ImageView title1.setVisibility(View.GONE);///TextView title2.setVisibility(View.GONE);///TextView title3.setVisibility(View.GONE);///TextView title4.setVisibility(View.GONE);///TextView title5.setVisibility(View.GONE);///TextView } private void showviews() { image.setVisibility(View.VISIBLE); title1

问题 I am writing a program in python that will take in specific formats, a Phone number and dollar/cent values. How can I make tkinter have default value which is permanent, not deletable. For example (XXX)-XXX-XXXX? basically you can add an entry to the widget but the entry is defined the permanent value like when its empty it looks like (_ _ _)-___-____ when it has text it looks like (434)-332-1234 回答1: If I understand you correctly, you want some sort of template in which a user can type his