weather

Does Yahoo Weather API needs an Consumer API Key?

拟墨画扇 提交于 2019-12-08 13:33:00
问题 I want to get data from the Weather API to know the forecast of an specific region. Using YQL Query I can get an Endpoint URL that returns the information I need, this doesn't seem to require a Consumer Key to work properly. I want to know if this is legal, and if not, what is the proper way to use my Consumer Key using YQL Query. This information will be used in an IOS App and as you know it takes over 8 days to be reviewed... The last thing I want is to get my app rejected because of this.

PHP-SQL查询上升的温度

我的未来我决定 提交于 2019-12-06 15:21:28
给定一个 Weather 表,编写一个 SQL 查询,来查找与之前(昨天的)日期相比温度更高的所有日期的 Id。 +---------+------------------+------------------+ | Id(INT) | RecordDate(DATE) | Temperature(INT) | +---------+------------------+------------------+ | 1 | 2015-01-01 | 10 | | 2 | 2015-01-02 | 25 | | 3 | 2015-01-03 | 20 | | 4 | 2015-01-04 | 30 | +---------+------------------+------------------+ 例如,根据上述给定的 Weather 表格,返回如下 Id: +----+ | Id | +----+ | 2 | | 4 | +----+ 来源:力扣(LeetCode) 子查询 SELECT Id FROM Weather as a where Temperature > (select Temperature from Weather as w where DATEDIFF(a.RecordDate, w.RecordDate) = 1 AND a.Temperature > w

Get location name by giving ZIP codes

时光怂恿深爱的人放手 提交于 2019-12-06 14:07:05
I need to display the location and city name when a user enters a ZIP Code. How do I get the corresponding location names? I would use a website like http://www.zipinfo.com/search/zipcode.htm and just send the zipcode to that, retrieve the input, parse for the city name, easy as that. Try the USPS zipcode API - http://www.usps.com/webtools/welcome.htm You can use the PlaceFinder geocoding web service to make REST based requests using the postal code you want to resolve to a name. The service supports both XML and JSON response formats . Here is a listing of the response elements returned by

Python using Kalman Filter to improve simulation but getting worse results

谁都会走 提交于 2019-12-06 05:55:17
I have questions on the behavior I am seeing with applying Kalman Filter (KF) to the following forecast problem. I have included a simple code sample. Goal: I would like to know if KF is suitable for improving forecast/simulation result for a day ahead (at t+24 hours), using the measurement result obtained now (at t). The goal is to get the forecast as close to measurement as possible Assumption: We assume the measurement is perfect (ie. if we can get the forecast matches the measurement perfectly, we are happy). We have a single measurement variable (z, real wind speed), and a single

Get weather update of current location?

為{幸葍}努か 提交于 2019-12-04 17:58:44
What I have: Latitude and Longitude. What I want: Get weather update for these coordinates. If you want to use the Google Weather API, you'll have to pass it either a City, State or a Zip code. To do this, you'll need to GeoCode your lat/long to get this info. Here's the URL to the Google Weather API: http://www.google.com/ig/api?weather=Seattle,WA Here's a sample code to take lat/long and convert to zip: Geocoder geocoder = new Geocoder(this, Locale.ENGLISH); List<Address> addresses = null; try { addresses = geocoder.getFromLocation(latitude, longitude, 3); } catch (IOException ex) { //Handle

How to meaningfully extract information from a JSON reply? [duplicate]

岁酱吖の 提交于 2019-12-04 05:57:20
问题 This question already has an answer here : Reading a JSON reply from WeatherUnderground (1 answer) Closed 6 years ago . Reply for Mumbai, India { "response": { "version": "0.1" "termsofService": "http://www.wunderground.com/weather/api/d/terms.html" "features": { "geolookup": 1 "conditions": 1 "forecast": 1 } } "location": { "type":"INTLCITY" "country":"IN" "country_iso3166":"IN" "country_name":"India" "state":"" "city":"Mumbai" "tz_short":"IST" "tz_long":"Asia/Kolkata" "lat":"19.12000084"

Is the AccuWeather API free for commercial use?

纵饮孤独 提交于 2019-12-03 15:56:25
I'd like to know if the AccuWeather API is free for commercial use. If not, how I can use it for commercial purposes? Is there a totally free weather API that I can use for my app? mattexx Accuweather data is not free. They will quote you for a custom service if you call their sales support. At one of my previous companies (circa 2007), we were able to get a contract with them for national hourly weather across their station network very cheap, but still not free. If you are looking for free weather APIs, Please have a look at weather underground . sakher I have looked in many weather data

How to refresh the weather layer?

匿名 (未验证) 提交于 2019-12-03 03:03:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Does anyone know if there is a way to refresh the Weather Layer in Google Maps javascript API? To give a little background, we have an application which stays open in the browser and updates some information on the map every few minutes. We let the users open the weather layer on the map, but the weather only loads once, when the layer is created. After a while, it gets outdated and we'd like it to stay current. I've tried everything from recreating the layer and setting the map to null, then back to the current map, but temperatures never

Python Weather API [closed]

不打扰是莪最后的温柔 提交于 2019-12-03 02:44:36
问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 6 years ago . How do I import weather data into a Python program? 回答1: Since Google has shut down its weather API, I suggest to check out OpenWeatherMap: The OpenWeatherMap service provides free weather data and forecast API

Accessing the underlying ActorRef of an akka stream Source created by Source.actorRef

匿名 (未验证) 提交于 2019-12-03 02:13:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I'm trying to use the Source.actorRef method to create an akka.stream.scaladsl.Source object. Something of the form import akka.stream.OverflowStrategy.fail import akka.stream.scaladsl.Source case class Weather(zip : String, temp : Double, raining : Boolean) val weatherSource = Source.actorRef[Weather](Int.MaxValue, fail) val sunnySource = weatherSource.filter(!_.raining) ... My question is: how do I send data to my ActorRef based Source object ? I assumed sending messages to the Source was something of the form //does not compile