prepared-statement

Attempting to learn mysqli prepared statements; what am I doing wrong?

旧街凉风 提交于 2020-02-05 06:22:02
问题 Here's the error I'm getting... Failed to prepare statement: (1064) You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '?.Pages WHERE slug='?'' at line 1 And here's my code... require_once("../database/config.php"); $pageSlug = "home"; $db = new mysqli(_DB_HOST, _DB_USER, _DB_PASSWORD, _DB_NAME); if ( $db->connect_errno ) { echo "Failed to connect to MySQL: (" . $db->connect_errno . ") " . $db->connect_error;

Creation of a prepared statement inside a loop

被刻印的时光 ゝ 提交于 2020-02-02 04:08:27
问题 For clarification: I know that it's the right thing to create the PreparedStatement outside the loop. I've asked this question just out of curiosity. Let's assume that I'm creating a PreparedStatement inside a loop with always the same SQL query. final String sql = "INSERT INTO ..."; while (condition) { ... PreparedStatement statement = connection.prepareStatement(sql); // Fill values of the prepared statement // Execute statement ... } Is this useless since the PreparedStatement object is

Creation of a prepared statement inside a loop

假装没事ソ 提交于 2020-02-02 04:08:07
问题 For clarification: I know that it's the right thing to create the PreparedStatement outside the loop. I've asked this question just out of curiosity. Let's assume that I'm creating a PreparedStatement inside a loop with always the same SQL query. final String sql = "INSERT INTO ..."; while (condition) { ... PreparedStatement statement = connection.prepareStatement(sql); // Fill values of the prepared statement // Execute statement ... } Is this useless since the PreparedStatement object is

Warning: mysqli_stmt::bind_param(): Number of variables doesn't match number of parameters in prepared statement in C:\User..\ on 148

﹥>﹥吖頭↗ 提交于 2020-01-30 13:25:09
问题 Hello i'm inserting a new column collegename, branch, and gender but suddenly it's giving me this error... Warning: mysqli_stmt::bind_param(): Number of variables doesn't match number of parameters in prepared statement in C:\Users\Raj\PhpstormProjects\usercake\models \class.newuser.php on line 148 What's that mean? actually i was inserting a new column into my database college , branch , year , and gender everything goes well but when i register myself it's shows the message your

PHP Prepared Statement insert or update If row exists

荒凉一梦 提交于 2020-01-30 12:30:40
问题 I have been searching for a fix for my code below. I have searched many similar post in stackoverflow but didn't get a work around. What I'm trying to establish is that, I want to check a query and if row exist I need to use UPDATE statement else INSERT statement. I have established this many time but without the prepared statement. Now that I'm modifying many of my previous codes with the prepared statements. Below is my code. <?php include'../db.php'; $exercise_days=$_POST['edays']; $id=$

C# Prepared Statements - @ sign (at / strudel sign) queries

南笙酒味 提交于 2020-01-29 12:33:45
问题 I Have a problem with a prepared statement in C#: OdbcCommand cmd = sql.CreateCommand(); cmd.CommandText = "SELECT UNIQUE_ID FROM userdetails WHERE USER_ID = ?"; cmd.Parameters.Add("@USER_ID", OdbcType.VarChar, 250).Value = email; (of course email contains a valid email address, with @ sign). This code returns a random error - "The connection has been disabled" {"ERROR [01000] [Microsoft][ODBC SQL Server Driver][TCP/IP Sockets]ConnectionWrite (send()). ERROR [08S01] [Microsoft][ODBC SQL

C# Prepared Statements - @ sign (at / strudel sign) queries

柔情痞子 提交于 2020-01-29 12:32:35
问题 I Have a problem with a prepared statement in C#: OdbcCommand cmd = sql.CreateCommand(); cmd.CommandText = "SELECT UNIQUE_ID FROM userdetails WHERE USER_ID = ?"; cmd.Parameters.Add("@USER_ID", OdbcType.VarChar, 250).Value = email; (of course email contains a valid email address, with @ sign). This code returns a random error - "The connection has been disabled" {"ERROR [01000] [Microsoft][ODBC SQL Server Driver][TCP/IP Sockets]ConnectionWrite (send()). ERROR [08S01] [Microsoft][ODBC SQL

mysqli_fetch_assoc() expects parameter / Call to a member function bind_param() errors. How to get the actual mysql error and fix it?

 ̄綄美尐妖づ 提交于 2020-01-26 04:41:06
问题 In my local/development environment, the MySQLi query is performing OK. However, when I upload it on my web host environment, I get this error: Fatal error: Call to a member function bind_param() on a non-object in... Here is the code: global $mysqli; $stmt = $mysqli->prepare("SELECT id, description FROM tbl_page_answer_category WHERE cur_own_id = ?"); $stmt->bind_param('i', $cur_id); $stmt->execute(); $stmt->bind_result($uid, $desc); To check my query, I tried to execute the query via

Null Pointer Exception for prepared statement Sql Connection in java

我的未来我决定 提交于 2020-01-25 11:00:28
问题 I have gone to same type of questions in this forum, but their solutions are not helping here. I am trying to run following code in java while trying to connect to MySql workbench: import java.sql.*; public class DBConnection { public static void main(String[] args) { Connection con = null; PreparedStatement st =null; try { Class.forName("com.mysql.jdbc.Driver"); con = DriverManager.getConnection("jdbc:mysql://localhost:3306/world","root","password"); String sql = "select * from city where id

Insert Data in Oracle DB using PHP

◇◆丶佛笑我妖孽 提交于 2020-01-25 10:51:12
问题 Inserting data in oracle DB using oci_8 . Sample query to insert string with special characters or quotes update TABLENAME set COMMENTS = 'As per Mark's email dated 28-Feb-2015 - Bill Gates & Team's effort' where ID = 99; To insert/update $query = 'update TABLENAME set COMMENTS = '$_POST[comments]'; $result = customexecute($new_query); public function customexecute($query) { $resutlt = parent::customquery($query); return $resutlt; } public static function customquery($query) { try{ $stmt =