prepared-statement

Insert Data in Oracle DB using PHP

亡梦爱人 提交于 2020-01-25 10:51:04
问题 Inserting data in oracle DB using oci_8 . Sample query to insert string with special characters or quotes update TABLENAME set COMMENTS = 'As per Mark's email dated 28-Feb-2015 - Bill Gates & Team's effort' where ID = 99; To insert/update $query = 'update TABLENAME set COMMENTS = '$_POST[comments]'; $result = customexecute($new_query); public function customexecute($query) { $resutlt = parent::customquery($query); return $resutlt; } public static function customquery($query) { try{ $stmt =

SQL Update Maria DB with Prepared Statement

非 Y 不嫁゛ 提交于 2020-01-25 03:49:07
问题 Please help.. I have search it. But I still don't know where is my fault. Maybe I just miss something. Here is the error : com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '?, ID_JABATAN=?, TANGGAL_MASUK=?, TANGGAL_KELUAR=?, ID_JENIS_KARYAWAN=? WHERE ID' at line 1 And this is my code : try { DBConnection knk = new DBConnection(); Connection conn =

Get result sql from Prepared Statement by Oracle

非 Y 不嫁゛ 提交于 2020-01-24 13:00:09
问题 I'm looking for posibility to get result sql (with injected parameter) from prepared statement in java for Oracle implementation. By MySQL the method toString() get wanted sql over the method asSql() from com.mysql.jdbc.PreparedStatement . But by Oracle implementation oracle.jdbc.driver.OraclePreparedStatementWrapper , I can't find the way to get a result sql. 回答1: I believe there's no such thing with the OraclePreparedStatement . If you absolutely need that feature, you could wrap some code

better way of using a single parameter multiple times in c#

假如想象 提交于 2020-01-22 17:51:12
问题 I'm new in using prepared statements for querying data from the database and I'm experiencing problems implementing parameters for c# specifically OracleParameters. So let's say I have the following SQL: string sql = "select * from table1 t1, table2 t2 where t1.columnX = @parm and t2.columnY = @parm" And the code is this: OracleCommand cmd = new OracleCommand(sql, conn); cmd.Parameters.Add(new OracleParameter("@parm", strParm)); The problem is when the cmd gets executed t1.columnX gets the

better way of using a single parameter multiple times in c#

大憨熊 提交于 2020-01-22 17:50:48
问题 I'm new in using prepared statements for querying data from the database and I'm experiencing problems implementing parameters for c# specifically OracleParameters. So let's say I have the following SQL: string sql = "select * from table1 t1, table2 t2 where t1.columnX = @parm and t2.columnY = @parm" And the code is this: OracleCommand cmd = new OracleCommand(sql, conn); cmd.Parameters.Add(new OracleParameter("@parm", strParm)); The problem is when the cmd gets executed t1.columnX gets the

Differences between using ? and :param in prepare statement

给你一囗甜甜゛ 提交于 2020-01-22 09:51:05
问题 Let's say I want to select records where Id = 30 . Prepared statements allow two ways of binding parameters: question marks $id = 30; $q = $conn->prepare("SELECT * FROM pdo_db WHERE id > ?"); $q->execute(array($id)); // Here above ID will be passed named parameters $sth = $conn->prepare("SELECT `id`, `title` FROM `pdo_db` WHERE `id` > :id"); $sth->execute(array( ':id' => 30 )); Both are working fine and give accurate results but I am not able to get the exact differences between these two nor

Workaround for “null primitives” in JDBC PreparedStatement? [duplicate]

霸气de小男生 提交于 2020-01-20 05:59:45
问题 This question already has answers here : Inserting null to an Integer column using JDBC (2 answers) Closed 2 years ago . When using raw JDBC, you can parameterize a PreparedStatement like so: PreparedStatement statement = connection.prepareStatement(someSQLString); String someString = getSomeString(); Integer int = getSomeInteger(); statement.setString(1, someString); statement.setLong(2, 5L); statement.setInt(3, int); ... Here, if someString is null , that's fine - strings are nullable. But

Workaround for “null primitives” in JDBC PreparedStatement? [duplicate]

假装没事ソ 提交于 2020-01-20 05:56:45
问题 This question already has answers here : Inserting null to an Integer column using JDBC (2 answers) Closed 2 years ago . When using raw JDBC, you can parameterize a PreparedStatement like so: PreparedStatement statement = connection.prepareStatement(someSQLString); String someString = getSomeString(); Integer int = getSomeInteger(); statement.setString(1, someString); statement.setLong(2, 5L); statement.setInt(3, int); ... Here, if someString is null , that's fine - strings are nullable. But

Workaround for “null primitives” in JDBC PreparedStatement? [duplicate]

假装没事ソ 提交于 2020-01-20 05:56:10
问题 This question already has answers here : Inserting null to an Integer column using JDBC (2 answers) Closed 2 years ago . When using raw JDBC, you can parameterize a PreparedStatement like so: PreparedStatement statement = connection.prepareStatement(someSQLString); String someString = getSomeString(); Integer int = getSomeInteger(); statement.setString(1, someString); statement.setLong(2, 5L); statement.setInt(3, int); ... Here, if someString is null , that's fine - strings are nullable. But

Why is MySQLi statements bind_param giving this error? [duplicate]

我们两清 提交于 2020-01-17 04:51:10
问题 This question already has answers here : mysqli_stmt::bind_param(): Number of elements in type definition string doesn't match number of bind variables (3 answers) Closed 2 years ago . Getting an error with my code found HERE... Which is a culmination of all the chatter from HERE which was "Answered" but did not fix my error. ($data is html form data) I have even gone out of my way to line up each variable, ?, DB column, and bind character in the hopes that it'll be a little more clearer. I