Why is MySQLi statements bind_param giving this error? [duplicate]

问题

This question already has answers here:

mysqli_stmt::bind_param(): Number of elements in type definition string doesn't match number of bind variables (3 answers)

Closed 2 years ago.

Getting an error with my code found HERE... Which is a culmination of all the chatter from HERE which was "Answered" but did not fix my error. ($data is html form data) I have even gone out of my way to line up each variable, ?, DB column, and bind character in the hopes that it'll be a little more clearer. I've went through and made sure that all the variables match up to string / int to match up with the database ( which is another error completely, but was brought up in the other thread ).

    DATABASE TABLE
    name        varchar(255)            
    cost        int(10)         
    perserv     int(5)          
    servings    int(10)         
    earns       int(10)         
    cp          int(10)         
    cooktime    varchar(11)         
    unlock      varchar(255)            
    special     varchar(255)            
    icon        varchar(255)            
    type        int(5)          
    options     varchar(255)            
    added       varchar(12)

Warning: mysqli_stmt::bind_param(): Number of variables doesn't match number of parameters in prepared statement

回答1:

Try removing the commas in your $bind variable.

$bind = 'siiiiissssiss';

来源：https://stackoverflow.com/questions/8686518/why-is-mysqli-statements-bind-param-giving-this-error