prepared-statement

Using sqlite3_bind_XXX inside a loop

会有一股神秘感。 提交于 2020-01-17 01:39:04
问题 I want to do multiple parameterized inserts with SQLite in my code. For this : I have a single prepare statement outside of my loop as : error = sqlite3_prepare(connection, insert_sql, strlen(insert_sql), &stmt, NULL); I want inserts within a loop as: while ( not reached end of datafile ) { // Insert into server table sqlite3_bind_int(stmt, 1, id1); sqlite3_bind_double(stmt, 2, latitude); sqlite3_bind_double(stmt, 3, longitude); sqlite3_step(stmt); } The API docs for the function : https:/

insert span values in database with PHP Prepared Statements

这一生的挚爱 提交于 2020-01-16 19:36:48
问题 I have a contact form where I have some checkboxes. After the user submits the form I want to get their entries in the database. I can do this properly, but today I wanted to change my form to be responsive. I changed my simple checkboxes to span tags, but now I can not get the values in the database. It did not give me any error but also did not show anything in the database. <html> <body> <form action="" method="POST" > <section> <div class="wrapper-checkbox"> <div class="checkbox"> <div

php bind_param is not working

余生颓废 提交于 2020-01-16 14:53:10
问题 i'm having weird results from php $stmt->bind_param, here is what happens... if i do this $status="something"; $var=5; $consulta="UPDATE carrito SET status='$status' WHERE id_carrito='$var'"; and prepare and execute it works... but as soon as i do this: $consulta="UPDATE carrito SET status=? WHERE id_carrito=?"; if($stmt=$mysqli->prepare($consulta)) { $stmt->bind_param("si",$status,$var); . . . it stops working, vars, are ok i print them after the execute and they have the correct value

What exactly does first parameter in bind_param() do?

吃可爱长大的小学妹 提交于 2020-01-15 09:27:49
问题 I am trying to understand prepared statements using PHP and mysqli. I tried to read on some tutorials, manual and this one: Bind_Param in PHP, but I have not yet found any satisfying answer. Someone wrote in answer as: When you prepare an SQL statement, you can insert a placeholder (?) where a column value would go, then use bind_param() to safely substitute that placeholder for the real column's value. This prevents any possibility of an SQL injection. I found some code in tutorials like

What exactly does first parameter in bind_param() do?

寵の児 提交于 2020-01-15 09:27:09
问题 I am trying to understand prepared statements using PHP and mysqli. I tried to read on some tutorials, manual and this one: Bind_Param in PHP, but I have not yet found any satisfying answer. Someone wrote in answer as: When you prepare an SQL statement, you can insert a placeholder (?) where a column value would go, then use bind_param() to safely substitute that placeholder for the real column's value. This prevents any possibility of an SQL injection. I found some code in tutorials like

Search feature with multiple criteria - PHP/MySQL

放肆的年华 提交于 2020-01-15 05:11:08
问题 How can i create a search page with multiple criteria where at least a criteria should be checked. Table Structure ID [pk] Name Sex Location I want to create a search form where user will be able to search by name or by name,sex or by name,sex,location or any such combination among [name,sex,location] How to design the query ? Edit i am not asking for checking atleast a single option has value [js validation], i am asking for the query ! I'll use mysqli prepared statement ! 回答1: You can check

Using bind_param with arrays and loops

 ̄綄美尐妖づ 提交于 2020-01-14 19:14:10
问题 according to this example for prepared statements I first bind parameters and then set values for the parameters. Let's assume I have a 2-dim array $alias $array1 = [ 'id' => 1, 'tstamp' => 123456789, 'alias' => '$alias', ]; $array2 = [ 'id' => 1, 'tstamp' => 123456789, 'alias' => '$alias2', ]; $alias = [$array1, $array2]; Why is this code working $insert = 'INSERT INTO abcdef VALUES (?,?,?)'; $insertStmt = $conn->prepare($insert); foreach ($alias as $array) { $insertStmt->bind_param('iis',

Cassandra nodejs DataStax driver don't return newly added columns via prepared statement execution

自古美人都是妖i 提交于 2020-01-14 12:43:12
问题 After adding a pair of columns in schema, I want to select them via select * . Instead select * returns old set of columns and none new. By documentation recommendation, I use {prepare: true} to smooth JavaScript floats and Cassandra ints/bigints difference (I don't really need the prepared statement here really, it is just to resolve this ResponseError : Expected 4 or 0 byte int issue and I also don't want to bother myself with query hints ). So on first execution of select * I had 3 columns

PDO - query giving no results

亡梦爱人 提交于 2020-01-14 05:18:09
问题 This is my prepared statment. SELECT `id`, `title`, `image`, `discount`, `price`, `new_price`, `img_url` FROM `deals` WHERE `active`="1" AND `category`=:ctid AND `img_url`!="" AND `Brands`=:p1 ORDER BY `order`, `id` ASC LIMIT 0, 12; This is the array that i am using in bindParam . Array ( [:ctid] => 1 [:p1] => Apple ) Here's the PHP code: $sql = 'SELECT `id`, `title`, `image`, `discount`, `price`, `new_price`, `img_url` FROM `deals` WHERE `active`="1" AND `category`=:ctid AND `img_url`!=""

SQL injection - how to use preparedstatement in java

自作多情 提交于 2020-01-13 07:30:09
问题 i have a SQL which is dynamically build,the following is the query : private String constructTownSearchQuery(String country, String stateName,String districtName,String townName) { StringBuilder statesSearchQuery = new StringBuilder(); statesSearchQuery.append(" select cntry.countryid,cntry.country,sta.stateid,sta.state,dst.districtid,dst.district,twn.townid,twn.town "); statesSearchQuery.append(" from m_countries as cntry,m_states as sta,m_districts as dst,m_towns as twn ");