merge | 易学教程

Python Pandas: How to merge based on an “OR” condition?

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问题 Let's say I have two dataframes, and the column names for both are: table 1 columns: [ShipNumber, TrackNumber, ShipDate, Quantity, Weight] table 2 columns: [ShipNumber, TrackNumber, AmountReceived] I want to merge the two tables based on both ShipNumber and TrackNumber. However, if i simply use merge in the following way (pseudo code, not real code): tab1.merge(tab2, "left", on=['ShipNumber','TrackNumber']) then, that means the values in both ShipNumber and TrackNumber columns from both

R: Trying to count the number of currencies in one data frame based on the positions of the other data frame

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问题 I have two data frames, X and Y . X <- data.frame(V1 = c("chr1", "chr1", "chr1", "chr2", "chr2", "ch2"), Start = c(0, 540, 920, 0, 582, 715 ), Stop = c(230, 720, 1270, 350, 635, 950)) Y <- data.frame(V1 = c("chr1", "chr1", "chr1", "chr2", "chr2", "ch2"), Start = c(3, 16, 180, 15, 585, 800 ), Stop = c(15, 24, 201, 102, 612, 850)) I want to obtain a data.frame Z which is a new data.frame with the info of X and the counts of Y between the range of each "X" row. For example, you can count 3 rows

Pandas merge creates unwanted duplicate entries

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问题 I'm new to Pandas and I want to merge two datasets that have similar columns. The columns are going to each have some unique values compared to the other column, in addition to many identical values. There are some duplicates in each column that I'd like to keep. My desired output is shown below. Adding how='inner' or 'outer' does not yield the desired result. import pandas as pd dict1 = {'A':[2,2,3,4,5]} dict2 = {'A':[2,2,3,4,5]} df1 = pd.DataFrame(dict1) df2 = pd.DataFrame(dict2) print(pd

How can I programmatically join 2 contacts in android?

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问题 I need to know if is it possible to join two or more contacts (in a programmatic way, using the Contacts android API or something). For example, I have a contact "Axel Rose" with an email account and a phone number, and I've noticed that some apps like whatsapp, Facebook and Skype are creating new contact entries for Axel Rose, instead of merging the existing one. I can join contacts using the "Join feature" from the phone, but is there a programmatic way? Thanks in advance. Cristian. 回答1:

git常用命令

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# 创建SSH Key（生成id_rsa私钥和id_rsa.pub公钥） ssh-keygen -t rsa -C "daiyuanpei@qq.com" # 查看所有分支 git branch -a # 切换分支到sign分支 git checkout remotes/origin/sign # 查看版本库状态，什么被修改过但还没提交的 git status # 查看当前相对上一次提交修改的内容 git diff # 把文件添加到仓库，此时是将修改添加到暂存区，可add多次 git add Task5.php # 把文件提交到仓库，此时是把暂存区的所有内容提交到当前分支，可一次提交多个文件 git commit -m "本次提交的备注" # 将本地的内容推送到远程库分支上 # 第一次推送分支所有内容 git push -u origin 分支名字 # 推送最新修改 git push origin 分支名字 git push origin HEAD:refs/for/xxx_1-0-163_BRANCH # 克隆代码 git clone 需要克隆的仓库地址 git clone http://gitlab.baidu.com/php/php.git # 查看远程仓库信息 git remote # 查看更加详细的信息 git remote -v # 版本回退 #

Combine two lists in a dataframe in R

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问题 I have two lists with different structure: listA <- list(c("a","b","c"), c("d","e")) listB <- list(0.05, 0.5) listA [[1]] [1] "a" "b" "c" [[2]] [1] "d" "e" listB [[1]] [1] 0.05 [[2]] [1] 0.5 I have an idea of how to use looping to combine both lists in a dataframe that looks like the one below but I'm sure that there is a more efficient way of doing this. data.frame(A = c("a","b","c","d","e"), B = c(rep(0.05,3), rep(0.5,2))) A B 1 a 0.05 2 b 0.05 3 c 0.05 4 d 0.50 5 e 0.50 回答1: This is

How to open .xcodeproj programmatically?

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问题 I have projects called A.xcodeproj, B.xcodeproj, C.xcodeproj now what is question, in AppDelegate of Project A , open project B and C on condition. int run; run = 0; if(run == 0) { Open project B.xcodeproj } else { Open project C.xcodeproj } Help Thanks in Advance. 回答1: on the command line use open to OPEN and SHOW xcode.. so in your case, when run == 0 when you want to BUILD the xcode project, invoke xcodebuild instead of open!.. so in your case, when run == 1 来源： https://stackoverflow.com

How to open .xcodeproj programmatically?

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Merge 2 dataframes by matching dates

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问题 I have two dataframes: id dates MUM-1 2015-07-10 MUM-1 2015-07-11 MUM-1 2015-07-12 MUM-2 2014-01-14 MUM-2 2014-01-15 MUM-2 2014-01-16 MUM-2 2014-01-17 and: id dates field1 field2 MUM-1 2015-07-10 1 0 MUM-1 2015-07-12 2 1 MUM-2 2014-01-14 4 3 MUM-2 2014-01-17 0 1 merged data: id dates field1 field2 MUM-1 2015-07-10 1 0 MUM-1 2015-07-11 na na MUM-1 2015-07-12 2 1 MUM-2 2014-01-14 4 3 MUM-2 2014-01-15 na na MUM-2 2014-01-16 na na MUM-2 2014-01-17 0 1 code: merge(x= df1, y= df2, by= 'id', all.x=

Git Step by Step – (8) Git的merge和rebase

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前面一篇文章中提到了"git pull"等价于"git fetch"加上"git merge"，然后还提到了pull命令支持rebase模式，这篇文章就介绍一下merge和rebase之间有什么差别。由于我们主要是想看看merge跟rebase之间的区别，这里就是用本地仓库的分支进行演示了。 merge 其实在介绍分支的那篇文章中已经介绍过了一些分支merge的内容，这里就进行一些补充和总结。下面我们基于本地一个仓库开始介绍，当前仓库的分支情况如下：其实，merge命令总结下来会有三种情况发生： merge命令不生效当目标分支是当前分支的祖先commit节点，也就是说当前分支已经是最新的了，在这种情况下merge命令没有任何效果。在当前仓库中，当我们把dev分支merge到master的时候，会得到"Already up-to-date." Fast-forward合并模式当前分支是目标分支的祖先commit节点时，会发生Fast-forward的merge，看下图这时的对象模型就更新了，这里merge的操作只是把dev分支的HEAD引用进行更新，指向最新的commit对象三方合并请参照"Git Step by Step – (5) Git分支(branch)"中分支合并的内容。如果没有冲突，Git会帮我们完成分支的合并，如果有冲突，就需要我们手动解决冲突了。