time-format

问题 Despite the fact that in http://<jenkins server>/systemInfo the user.timezone property value meets my actual time zone I still have 12-hour clock format. I would like to have 24-hour clock format instead. Does anyone have any ideas how it can be changed in Jenkins? Thank you. 回答1: As @Arkain mentioned, you should specify in browser's settings the language which suits your intended time format. I had both English (US) and just English (which I thought was English (GB)), but then I realized

问题 My parser may encounter "2:37PM" (parsed by "H:mma") or "02:37PM" (parsed by "hh:mma"). How can I parse both without resorting to a try-catch? I receive an error like this when I get it wrong: Conflict found: Field AmPmOfDay 0 differs from AmPmOfDay 1 derived from 02:37 回答1: First of all, the error you get is caused by the H in your pattern, which parses hours in 24-hour format and gets into trouble if you put an a (for AM/PM) at the end of the pattern. You can use java.time to parse the

问题 My parser may encounter "2:37PM" (parsed by "H:mma") or "02:37PM" (parsed by "hh:mma"). How can I parse both without resorting to a try-catch? I receive an error like this when I get it wrong: Conflict found: Field AmPmOfDay 0 differs from AmPmOfDay 1 derived from 02:37 回答1: First of all, the error you get is caused by the H in your pattern, which parses hours in 24-hour format and gets into trouble if you put an a (for AM/PM) at the end of the pattern. You can use java.time to parse the

来源： https://stackoverflow.com/questions/60740996/detect-if-users-locale-is-set-to-12-hour-or-24-hour-timeformat-using-javascript

来源： https://stackoverflow.com/questions/56302402/java-text-parseexception-unparseable-date-200100-000z

问题 I have a flight itinerary program where I need to get difference between departure and arrival time. I get these specified times as String from the data. Here is my problem: import static java.time.temporal.ChronoUnit.MINUTES; import java.time.LocalTime; import java.time.format.DateTimeFormatter; public class test2 { public static void main(String[] args) { DateTimeFormatter dateFormat = DateTimeFormatter.ofPattern("HHmm"); LocalTime departure = LocalTime.parse("1139", dateFormat); LocalTime

问题 I am having trouble using java's LocalTime to parse a string with hours, minutes, and seconds. LocalTime t = LocalTime.parse("8:30:17"); // Simplification This throws the following exception: Exception in thread "main" java.time.format.DateTimeParseException: Text '8:30:17' could not be parsed at index 0 回答1: You'll need to pass in a custom DateTimeFormatter like this: DateTimeFormatter formatter = DateTimeFormatter.ofPattern("H:mm:ss"); LocalTime t = LocalTime.parse(times.get(i), formatter);

问题 I am having trouble using java's LocalTime to parse a string with hours, minutes, and seconds. LocalTime t = LocalTime.parse("8:30:17"); // Simplification This throws the following exception: Exception in thread "main" java.time.format.DateTimeParseException: Text '8:30:17' could not be parsed at index 0 回答1: You'll need to pass in a custom DateTimeFormatter like this: DateTimeFormatter formatter = DateTimeFormatter.ofPattern("H:mm:ss"); LocalTime t = LocalTime.parse(times.get(i), formatter);

问题 I have some issue with negative times in gnuplot. Basically, I would like to write a negative time, e.g. as -00:01:00 , but gnuplot is not interpreting it as -60 seconds, but as +60 seconds. I can somehow understand why: because -00 hours is equal to +00 hours and then 01 minutes are counted positive. Did I overlook something? Is there maybe an easy workaround? More examples are given below. Let's convert some times in the format %H:%M:%S (actually %tH:%tM:%tS ). I'm fine with all lines,

问题 I have a decimal value in minutes with the value 3361 and need to convert in hours and present in this format: 56:01:00 I tried this code: $scope.myTime = new Date(1970, 0, 1).setMinutes(3361); <input type="text" class="form-control" ng-model="myTime | date:'HH:mm:ss'"> But the result is not that I expected: 08:01:00 回答1: I fear that you can't acheive what you need using angular date filter. You can create you custom filter (here angular official guide) and build the result in the format you