Pandas merge creates unwanted duplicate entries

好久不见. 提交于 2020-01-23 00:58:42

问题


I'm new to Pandas and I want to merge two datasets that have similar columns. The columns are going to each have some unique values compared to the other column, in addition to many identical values. There are some duplicates in each column that I'd like to keep. My desired output is shown below. Adding how='inner' or 'outer' does not yield the desired result.

import pandas as pd

dict1 = {'A':[2,2,3,4,5]}
dict2 = {'A':[2,2,3,4,5]}

df1 = pd.DataFrame(dict1)
df2 = pd.DataFrame(dict2)

print(pd.merge(df1,df2))

output:
   A
0  2
1  2
2  2
3  2
4  3
5  4
6  5

desired/expected output:
   A
0  2
1  2
2  3
3  4
4  5

Please let me know how/if I can achieve the desired output using merge, thank you!

EDIT Wow a lot of comments on this. To clarify why I'm confused about this behavior, if I simply add another column, it doesn't make four 2's but rather there are only two 2's, so I would expect that in my first example it would also have the two 2's. Why does the behavior seem to change, what's pandas doing?

import pandas as pd
dict1 = {'A':[2,2,3,4,5],
         'B':['red','orange','yellow','green','blue'],
        }
dict2 = {'A':[2,2,3,4,5],
         'B':['red','orange','yellow','green','blue'],
        }

df1 = pd.DataFrame(dict1)
df2 = pd.DataFrame(dict2)

print(pd.merge(df1,df2))

output:
   A       B
0  2     red
1  2  orange
2  3  yellow
3  4   green
4  5    blue

However, based on the first example I would expect:
   A       B
0  2     red
1  2  orange
2  2     red
3  2  orange
4  3  yellow
5  4   green
6  5    blue

回答1:


import pandas as pd

dict1 = {'A':[2,2,3,4,5]}
dict2 = {'A':[2,2,3,4,5]}

df1 = pd.DataFrame(dict1).reset_index()
df2 = pd.DataFrame(dict2).reset_index()

df = df1.merge(df2, on = 'A')
df = pd.DataFrame(df[df.index_x==df.index_y]['A'], columns=['A']).reset_index(drop=True)

print(df)

Output:

   A
0  2
1  2
2  3
3  4
4  5



回答2:


dict1 = {'A':[2,2,3,4,5]}
dict2 = {'A':[2,2,3,4,5]}

df1 = pd.DataFrame(dict1)
df1['index'] = [i for i in range(len(df1))]
df2 = pd.DataFrame(dict2)
df2['index'] = [i for i in range(len(df2))]

df1.merge(df2).drop('index', 1, inplace = True)

The idea is to merge based on the matching indices as well as matching 'A' column values.
Previously, since the way merge works depends on matches, what happened is that the first 2 in df1 was matched to both the first and second 2 in df2, and the second 2 in df1 was matched to both the first and second 2 in df2 as well.

If you try this, you will see what I am talking about.

dict1 = {'A':[2,2,3,4,5]}
dict2 = {'A':[2,2,3,4,5]}

df1 = pd.DataFrame(dict1)
df1['index'] = [i for i in range(len(df1))]
df2 = pd.DataFrame(dict2)
df2['index'] = [i for i in range(len(df2))]

df1.merge(df2, on = 'A')



回答3:


did you try df.drop_duplicates() ?

import pandas as pd

dict1 = {'A':[2,2,3,4,5]}
dict2 = {'A':[2,2,3,4,5]}

df1 = pd.DataFrame(dict1)
df2 = pd.DataFrame(dict2)

df=pd.merge(df1,df2)
df_new=df.drop_duplicates() 
print df
print df_new

Seems that it gives the results that you want



来源:https://stackoverflow.com/questions/42444078/pandas-merge-creates-unwanted-duplicate-entries

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