concatenation

问题 I have 3 20x2 double arrays A , B and C . I want to combine them in one 3d array D so that D(:,:,1) will return A , D(:,:,2) will return B and D(:,:,3) will return C . 回答1: Using cat to concatenate along the third dimension might be the elegant way - D = cat(3,A,B,C) Here, the first input argument 3 specifies the dimension along which the concatenation is to be performed. 回答2: Like this? A = 1*ones(20,2); B = 2*ones(20,2); C = 3*ones(20,2); D = zeros(20,2,3); % Preallocate the D Matrix D(:,:

问题 I have a resource file where needed create string define with concatenation macros and string, something like this #define _STRINGIZE(n) #n #define STRINGIZE(n) _STRINGIZE(n) #define Word_ Word 100 DIALOGEX 0, 0, 172, 118 STYLE DS_SETFONT | DS_MODALFRAME | WS_POPUP | WS_CAPTION | WS_SYSMENU CAPTION "Hello"STRINGIZE(Word_)=>"Hello"Word" but needed simple "HelloWord" without average quotes. 回答1: For anyone who cares: a .rc file is a resource file from an MFC project that defines UI elements,

问题 I have a resource file where needed create string define with concatenation macros and string, something like this #define _STRINGIZE(n) #n #define STRINGIZE(n) _STRINGIZE(n) #define Word_ Word 100 DIALOGEX 0, 0, 172, 118 STYLE DS_SETFONT | DS_MODALFRAME | WS_POPUP | WS_CAPTION | WS_SYSMENU CAPTION "Hello"STRINGIZE(Word_)=>"Hello"Word" but needed simple "HelloWord" without average quotes. 回答1: For anyone who cares: a .rc file is a resource file from an MFC project that defines UI elements,

问题 I'm learning Python now, yay! Anyway, I have small problem. I don't see problem in here: x = 3 y = 7 z = 2 print "I told to the Python, that the first variable is %d!" % x print "Anyway, 2nd and 3rd variables sum is %d. :)" % y + z But Python thinks different - TypeError: cannot concatenate 'str' and 'int' objects . Why is that so? I haven't setted any variable as string... as much as I see. 回答1: % has a higher precedence than + , so s % y + z is parsed as (s % y) + z . If s is a string, then

问题 I have problems to concatenate NSString. Each time I pushed a button I want that something ("aux") is added to my string ("myString"). so: NSString *aux = [NSString stringWithFormat: @"%d", buttonIndex]; myString=[NSString stringWithFormat:@"%@/%@",posTargetaText,aux]; aux = nil; The first time i pushed the button it works good but the second it doesn't work. Some help please? 回答1: So you can certainly use stringWithFormat , but why don't you use stringByAppendingString instead, since that's

问题 I am trying to concat two dataframe, horizontally. df2 contains 2 result variables for every observation in df1. df1.shape (242583, 172) df2.shape (242583, 2) My code is: Fin = pd.concat([df1, df2], axis= 1) But somehow the result is stacked in 2 dimensions: Fin.shape (485166, 174) What am I missing here? 回答1: There are different index values, so indexes are not aligned and get NaN s: df1 = pd.DataFrame({ 'A': ['a','a','a'], 'B': range(3) }) print (df1) A B 0 a 0 1 a 1 2 a 2 df2 = pd

问题 Consider the following line of code: <?php $x = 10; $y = 7; echo '10 - 7 = '.$x-$y; ?> The output of that is 3, which is the expected result of the calculation $x-$y. However, the expected output is: 10 - 7 = 3 My question therefore is, what happened to the string that I'm concatenating with the calculation? I know that in order to produce the result I expected, I need to enclose the arithmetic operation in parenthesis: <?php $x = 10; $y = 7; echo '10 - 7 = '.($x-$y); ?> outputs 10 - 7 = 3

问题 Consider the following line of code: <?php $x = 10; $y = 7; echo '10 - 7 = '.$x-$y; ?> The output of that is 3, which is the expected result of the calculation $x-$y. However, the expected output is: 10 - 7 = 3 My question therefore is, what happened to the string that I'm concatenating with the calculation? I know that in order to produce the result I expected, I need to enclose the arithmetic operation in parenthesis: <?php $x = 10; $y = 7; echo '10 - 7 = '.($x-$y); ?> outputs 10 - 7 = 3

问题 This question already has answers here : string concatenation in css (5 answers) Closed 2 years ago . How can I concatenate the CSS attr() selector with static text in a url() field? The HTML I use: <div image='/Require/static.png'></div> //Example 2 <div image='static.png'></div> //Example 3, 4, 5 For example: //image attribute contains the image name (and prefix location when needed, see example 2) div[image]:before { background-image: url('/Image/static.png'); //Works background-image: url

问题 I am working with Hadoop 0.20.2 and would like to concatenate two files into one using the -cat shell command if possible (source: http://hadoop.apache.org/common/docs/r0.19.2/hdfs_shell.html) Here is the command I'm submitting (names have been changed): **/path/path/path/hadoop-0.20.2> bin/hadoop fs -cat /user/username/folder/csv1.csv /user/username/folder/csv2.csv > /user/username/folder/outputdirectory/** It returns bash: /user/username/folder/outputdirectory/: No such file or directory I