concatenation

How can I concatenate two files in hadoop into one using Hadoop FS shell?

耗尽温柔 提交于 2019-12-19 06:19:13
问题 I am working with Hadoop 0.20.2 and would like to concatenate two files into one using the -cat shell command if possible (source: http://hadoop.apache.org/common/docs/r0.19.2/hdfs_shell.html) Here is the command I'm submitting (names have been changed): **/path/path/path/hadoop-0.20.2> bin/hadoop fs -cat /user/username/folder/csv1.csv /user/username/folder/csv2.csv > /user/username/folder/outputdirectory/** It returns bash: /user/username/folder/outputdirectory/: No such file or directory I

How can I concatenate two files in hadoop into one using Hadoop FS shell?

橙三吉。 提交于 2019-12-19 06:19:10
问题 I am working with Hadoop 0.20.2 and would like to concatenate two files into one using the -cat shell command if possible (source: http://hadoop.apache.org/common/docs/r0.19.2/hdfs_shell.html) Here is the command I'm submitting (names have been changed): **/path/path/path/hadoop-0.20.2> bin/hadoop fs -cat /user/username/folder/csv1.csv /user/username/folder/csv2.csv > /user/username/folder/outputdirectory/** It returns bash: /user/username/folder/outputdirectory/: No such file or directory I

R: What are the best functions to deal with concatenating and averaging values in a data.frame?

为君一笑 提交于 2019-12-19 04:06:13
问题 I have a data.frame from this code: my_df = data.frame("read_time" = c("2010-02-15", "2010-02-15", "2010-02-16", "2010-02-16", "2010-02-16", "2010-02-17"), "OD" = c(0.1, 0.2, 0.1, 0.2, 0.4, 0.5) ) which produces this: > my_df read_time OD 1 2010-02-15 0.1 2 2010-02-15 0.2 3 2010-02-16 0.1 4 2010-02-16 0.2 5 2010-02-16 0.4 6 2010-02-17 0.5 I want to average the OD column over each distinct read_time (notice some are replicated others are not) and I also would like to calculate the standard

How to concatenate multiple Python source files into a single file?

一个人想着一个人 提交于 2019-12-18 18:33:22
问题 (Assume that: application start-up time is absolutely critical; my application is started a lot; my application runs in an environment in which importing is slower than usual; many files need to be imported; and compilation to .pyc files is not available.) I would like to concatenate all the Python source files that define a collection of modules into a single new Python source file. I would like the result of importing the new file to be as if I imported one of the original files (which

How to concatenate multiple Python source files into a single file?

泪湿孤枕 提交于 2019-12-18 18:33:13
问题 (Assume that: application start-up time is absolutely critical; my application is started a lot; my application runs in an environment in which importing is slower than usual; many files need to be imported; and compilation to .pyc files is not available.) I would like to concatenate all the Python source files that define a collection of modules into a single new Python source file. I would like the result of importing the new file to be as if I imported one of the original files (which

SQL Help: Select statement Concatenate a One to Many relationship

不羁的心 提交于 2019-12-18 18:26:24
问题 For example I have two tables. The first table is student while the second table are the courses that the a student is taking. How can I use a select statement so that I can see two columns student and courses so that the courses are separated by commas. Thanks. 回答1: Assuming you're using SQL Server 2005: This should do what you're after - obviously replace fields as you need: For demo purposes, consider the following two table structures: Students( STU_PKEY Int Identity(1,1) Constraint PK

overloaded operator << on ofstream concatenation problems

孤者浪人 提交于 2019-12-18 16:50:59
问题 I have the following code: struct simple { simple (int a1, int a2) : member1(a1), member2(a2) {} int member1; int member2; }; std::ofstream &operator << (std::ofstream &f, const simple &obj) { f<<obj.member1<<", "<<obj.member2; return f; } int main(int argc, const char *argv[]) { std::ofstream f("streamout.txt"); simple s(7,5); f << s; //#1 This works f << "label: " << s; //#2 This fails return 0; } I'm trying to understand why #1 works, while there are problems when trying to use the

SQL using If Not Null on a Concatenation

て烟熏妆下的殇ゞ 提交于 2019-12-18 14:54:35
问题 If I have the table SELECT (Firstname || '-' || Middlename || '-' || Surname) AS example_column FROM example_table This will display Firstname-Middlename-Surname e.g. John--Smith Jane-Anne-Smith The second one (Jane’s) displays correct, however since John doesn’t have a middlename, I want it to ignore the second dash. How could I put a sort of IF Middlename = NULL statement in so that it would just display John-Smith 回答1: Here would be my suggestions: PostgreSQL and other SQL databases where

I'm trying out Grunt and need a simple way to concatenate my modules

时光总嘲笑我的痴心妄想 提交于 2019-12-18 14:50:20
问题 This is my first time using Grunt and I'd like to have it combine all my js modules, each of which is wrapped in an immediately executing function, containing a 'use strict' declaration and put them into one file, wrapped up in only one immediately executing function, with only one 'use strict' declaration. How is this normally done? I figured this would be a common use case? Perhaps I'm going about things the wrong way? Should I be using one of the module loading formats (i.e. commonjs, amd)

grunt-concat separator option?

扶醉桌前 提交于 2019-12-18 12:23:56
问题 how to specify a separator in this scenario: I'm concatenating my files with grunt-concat this way: concat: { options: { banner: '<%= banner %>', separator: "" }, dist: { files:{ '<%= distdir %>/public/scripts/ieditor.js': [ 'public/scripts/ieditor/vars.js', 'public/scripts/ieditor/controllers/*.js', 'public/scripts/ieditor/directives/*.js', 'public/scripts/ieditor/app.js', 'public/scripts/ieditor/services/*.js', 'public/scripts/ieditor/filters/*.js' ], '<%= distdir %>/public/scripts