concatenation

问题 How to split string at comma so that it keeps all spaces. Example: Input: [" hello , world "] Need to separate this in array so that it looks like this: Array[0] = " hello " Array[1] = " world " and after connecting them: Output: " hello world " Tried using split like this: input.split("\\s*,\\s*")) but then I get it separated without white space... Array[0] = "hello" Array[1] = "world" Any ideas how to do this? 回答1: String s = " hello , world "; String s1[] = s.split(","); System.out.println

问题 How to split string at comma so that it keeps all spaces. Example: Input: [" hello , world "] Need to separate this in array so that it looks like this: Array[0] = " hello " Array[1] = " world " and after connecting them: Output: " hello world " Tried using split like this: input.split("\\s*,\\s*")) but then I get it separated without white space... Array[0] = "hello" Array[1] = "world" Any ideas how to do this? 回答1: String s = " hello , world "; String s1[] = s.split(","); System.out.println

问题 I have a collection of source strings that I wish to concatenate into one destination string. The source collection looks as follows: { "a", "b", "c" } I want the output string to be: abc But sometimes, I want a separator as well. So for the same input, now the output is to be: a-b-c And finally, the input sometimes needs to be enclosed in other characters, in this case [] , causing the output to be: [a]-[b]-[c] An empty source collection should yield an empty string. How would I go about

问题 Straight into business: I have code looking roughly like this: char* assemble(int param) { char* result = "Foo" << doSomething(param) << "bar"; return result; } Now what I get is: error: invalid operands of types ‘const char [4]’ and ‘char*’ to binary ‘operator<<’ Edit: doSomething returns a char* . So, how do I concatenate these two? Additional info: Compiler: g++ 4.4.5 on GNU/Linux 2.6.32-5-amd64 回答1: "Foo" and "Bar" are literals, they don't have the insertion ( << ) operator. you instead

问题 I'm kinda new to JavaFX and currently trying to do a Calendar application for a school project. I was wondering if there was a way to concatenate a fx:id such a @FXML private Label Box01; (In function) String ExampleNum = "01"; (Box+ExampleNum).setText("Test"); 回答1: In addition to the methods mentioned by @jewelsea here are 2 more ways to do this: Create & inject a Map containing the boxes as values from the fxml: <VBox xmlns:fx="http://javafx.com/fxml/1" fx:controller="fxml.Controller">

问题 I want to refactor: const char* arr = "The " "quick " "brown"; into something like: const char* quick = "quick "; const char* arr = "The " quick "brown"; because the string "quick" is used is many other places. Ideally I need to be able to do this with just const primitive types, so no string. What is the best way to do this? 回答1: Compiling the comments in the form of an answer: Use a macro. #define QUICK "quick " char const* arr = "The " QUICK "brown"; Use std:string . std::string quick =

问题 I'm using MS-Access 2003 with the query creator. I select everything from one table ( FaitsSaillants ), then one specific row ( WHERE VARIABLE='TitreMandat' ) from another table ( tb_SOMMAIRE ). I want to select another row from that second table and concatenate it. The query PARAMETERS [CurrAxe] Text ( 255 ), [CurrOTP] Text ( 255 ), [CurrClient] Text ( 255 ), [StartDate] DateTime, [EndDate] DateTime; SELECT tb_SOMMAIRE.Valeur AS Projet, tb_SOMMAIRE.VARIABLE, * FROM (FaitsSaillants LEFT JOIN

问题 I am having a problem with a particular line of code: ActiveSheet.Range("A" & rowCount & ":" & Mid(alphabet, totHdrLngth, 1) & belowRowCount) Where alphabet is a string containing uppercase letters A to Z. I keep getting the following error: Run-time error '5': Invalid Procedure call or argument I tried creating a String "inRange" and changing the code to this: inRange = "A" & rowCount & ":" & Mid(alphabet, totHdrLngth, 1) & belowRowCount curRange = ActiveSheet.Range(inRange) But that did not

问题 This might be a silly question but it struck me, and here i ask. <?php $x="Hi"; $y=" There"; $z = $x.$y; $a = "$x$y"; echo "$z"."<br />"."$a"; ?> $z uses the traditional concatenation operator provided by php and concatenates, conversely $a doesn't, My questions: by not using the concatenation operator, does it effect the performance? If it doesn't why at all have the concatenation operator. Why have 2 modes of implementation when one does the work? 回答1: Only slightly, since PHP has to parse

问题 I have following lines of code and I want to use visibleoffer variable as selector. How can I concatenate it? var visibleoffer = '.' + obj.parents('tbody').attr('providername') + ' .visible-offers'; //visibleoffer = .Txy .visible-offers $(obj).parents('.Provider').find(".Offers:not(.HideByProviderFilter,.HideByMainFilter,.HideByProviderFilter.HideByMainFilter,+ visibleoffer)").length; So it becomes: $(obj).parents('.Provider').find(".Offers:not(.HideByProviderFilter,.HideByMainFilter,