clone

Solid tutorial for building a simple wiki application in Ruby on Rails? [closed]

空扰寡人 提交于 2019-12-03 08:36:28
Closed. This question is off-topic. It is not currently accepting answers. Learn more . Want to improve this question? Update the question so it's on-topic for Stack Overflow. I've searched and I've found a lot that are antiquated. Any suggestions? You can easily create a wiki with zena (a rails CMS): You create an empty application with zena wiki You initialize an empty database cd wiki; rake zena:init RAILS_ENV=production You set the publish, write and read groups of a node to "public" (use the wrench tool, "drive" tab) You change the anonymous user's status from "moderated" to "user" (user

jQuery .wrap() not wrapping around a cloned element

£可爱£侵袭症+ 提交于 2019-12-03 06:38:29
(function($) { $.extend({ notify: function(options, duration) { var defaults = { inline: true, href: '', html: '' }; var options = $.extend(defaults, options); var body = $('body'), container = $('<ul></ul>').attr('id', 'notification_area'), wrapper = '<li class="notification"></li>', clone; if (!body.hasClass('notifications_active')) { body.append(container).addClass('notifications_active'); } if (options.inline == true && options.href) { clone = $(options.href).clone().wrap(wrapper); } clone.css('visibility', 'hidden').appendTo(container); var clone_height = 0 - parseInt(clone.outerHeight())

How to clone an array of objects in PHP?

∥☆過路亽.° 提交于 2019-12-03 06:13:58
问题 I have an array of objects. I know that objects get assigned by "reference" and arrays by "value". But when I assign the array, each element of the array is referencing the object, so when I modify an object in either array the changes are reflected in the other. Is there a simple way to clone an array, or must I loop through it to clone each object? 回答1: References to the same objects already get copied when you copy the array. But it sounds like you want to shallow-copy deep-copy the

What is the easiest way to deeply clone (copy) a mutable Scala object?

耗尽温柔 提交于 2019-12-03 05:48:56
What is the easiest way to deeply clone (copy) a mutable Scala object? Since you want the easiest way to deep copy a Scala object and not the fastest, you can always serialize the object, provided that it's serializable, and then deserialize it back. The following code only runs when compiled, not in REPL. def deepCopy[A](a: A)(implicit m: reflect.Manifest[A]): A = util.Marshal.load[A](util.Marshal.dump(a)) val o1 = new Something(...) // "Something" has to be serializable val o2 = deepCopy(o1) A Java-specific solution (which should work great in Scala too), is the Cloner library . It's fast,

How to Clone Models in Backbone

守給你的承諾、 提交于 2019-12-03 05:36:12
I have a model which can be edited by a certain view; however, at the bottom of the view the user should get an option to save or discard all changes. This means that you will need to store a list of all the changes to be made to the model and then make those changes only once the 'save' button has been clicked. This sounds unnecessarily complicated and I have come up with an idea of an alternative approach which is to create a clone of the model and make changes to that in the view. Then if the user clicks 'save' delete the old model and replace it in its collection with the new one,

How to copy java.util.list Collection

这一生的挚爱 提交于 2019-12-03 05:26:22
问题 I am implementing a Java class responsible for ordering java.util.List. The problem comes when I use this class. I'm able to ordering the list but I want to copy the "original" list without modification so that I could register every change made on the original list. The sorted list contains object and one of its fields stores a classification id, and this id it is updated with the index value of the list. I tried to use clone method and it keeps the list unsorted but the changes made on

How to clone ES6 generator? [duplicate]

隐身守侯 提交于 2019-12-03 05:24:28
This question already has answers here : Implementing monads in JavaScript (3 answers) I'm trying to create a List monad in ES6 using generators. To make it work I need to create a copy of an iterator that has already consumed several states. How do I clone an iterator in ES6? function* test() { yield 1; yield 2; yield 3; } var x = test(); console.log(x.next().value); // 1 var y = clone(x); console.log(x.next().value); // 2 console.log(y.next().value); // 2 (sic) I've tried clone and cloneDeep from lodash , but they were of no use. Iterators that are returned in this way are native functions

how to clone content of a div to another div

陌路散爱 提交于 2019-12-03 04:50:15
问题 I want to copy the content of a selected div to another div with jquery clone. but I dont want to append it anywhere what I mean is when we make a clone of a div with jquery (correct me if i am wrong) we have to set its position and it will dynamically create a new division which is displayed. but I want to get the content of a selected div and copy it to another pre-set div 回答1: var a = $('#selector').html(); var b = $('#selector').html(a); not sure I understood you properly but I think

When is clone() and fork better than pthreads?

淺唱寂寞╮ 提交于 2019-12-03 04:28:54
问题 I am beginner in this area. I have studied fork() , vfork() , clone() and pthreads. I have noticed that pthread_create() will create a thread, which is less overhead than creating a new process with fork() . Additionally the thread will share file descriptors, memory, etc with parent process. But when is fork() and clone() better than pthreads? Can you please explain it to me by giving real world example? Thanks in Advance. 回答1: The strength and weakness of fork (and company) is that they

Efficient way to clone a HashSet<T>?

强颜欢笑 提交于 2019-12-03 01:02:34
A few days ago, I answered an interesting question on SO about HashSet<T> . A possible solution involved cloning the hashset, and in my answer I suggested to do something like this: HashSet<int> original = ... HashSet<int> clone = new HashSet<int>(original); Although this approach is quite straightforward, I suspect it's very inefficient: the constructor of the new HashSet<T> needs to separately add each item from the original hashset, and check if it isn't already present . This is clearly a waste of time: since the source collection is a ISet<T> , it is guaranteed not to contain duplicates.