How to clone an array of objects in PHP?

问题

I have an array of objects. I know that objects get assigned by "reference" and arrays by "value". But when I assign the array, each element of the array is referencing the object, so when I modify an object in either array the changes are reflected in the other.

Is there a simple way to clone an array, or must I loop through it to clone each object?

回答1:

References to the same objects already get copied when you copy the array. But it sounds like you want to ~~shallow-copy~~ deep-copy the objects being referenced in the first array when you create the second array, so you get two arrays of distinct but similar objects.

The most intuitive way I can come up with right now is a loop; there may be simpler or more elegant solutions out there:

$new = array();

foreach ($old as $k => $v) {
    $new[$k] = clone $v;
}

回答2:

$array = array_merge(array(), $myArray);

回答3:

You need to clone objects to avoid having references to the same object.

function array_copy($arr) {
    $newArray = array();
    foreach($arr as $key => $value) {
        if(is_array($value)) $newArray[$key] = array_copy($value);
        else if(is_object($value)) $newArray[$key] = clone $value;
        else $newArray[$key] = $value;
    }
    return $newArray;
}

回答4:

As suggested by AndreKR, using array_map() is the best way to go if you already know that your array contains objects:

$clone = array_map(function ($object) { return clone $object; }, $array);

回答5:

I opted for clone as well. Cloning an array does not work (you could consider some arrayaccess implementation to do so for you), so as for the array clone with array_map:

class foo {
    public $store;
    public function __construct($store) {$this->store=$store;}
}

$f = new foo('moo');
$a = array($f);

$b = array_map(function($o) {return clone $o;}, $a);

$b[0]->store='bar';    
var_dump($a, $b);

Array clone with serialize and unserialize

If your objects support serialisation, you can even sort of deep shallow copy/clone with a tour into their sleeping state and back:

$f = new foo('moo');
$a = array($f);

$b = unserialize(serialize($a));

$b[0]->store='bar';
var_dump($a, $b);

However, that can be a bit adventurous.

回答6:

You need to loop it (possibly using a function like array_map() for that), there is no PHP function to automatically perform a deep copy of an array.

回答7:

I've done it like this:

function array_clone($array) {
    array_walk_recursive($array, function(&$value) {
        if(is_object($value)) {
            $value = clone $value;
        }
    });
    return $array;
}

The function arg copies the array without cloning the objects, then each nested object is cloned. So it won't work if the algorithm is not used inside a function.

Note this function clone the array recursively. You can use array_walk instead of array_walk_recursive if you do not want this to happen.

回答8:

Here is my best practice on an array of objects and cloning. Usually it is a good idea, to have a Collection class for each class of objects (or interface), which are used in an array. With the magic function __clone cloning becomes a formalized routine:

class Collection extends ArrayObject
{
     public function __clone()
     {
        foreach ($this as $key => $property) {
            $this[$key] = clone $property;
        }
     }
}

To clone your array, use it as Collection and then clone it:

$arrayObject = new Collection($myArray);
$clonedArrayObject = clone $arrayObject;

One step further, you should add a clone method to your class and each sub-class, too. This is important for deep cloning, or you might have unintended side effects:

class MyClass
{
     public function __clone()
     {
        $this->propertyContainingObject = clone $this->propertyContainingObject;
     }
}

An important note on using ArrayObject is, that you cannot use is_array() any longer. So be aware of this on refactoring your code.

回答9:

or also

$nuarr = json_decode(json_encode($array));

but it is expensive, I prefer Sebastien version (array_map)

回答10:

Objects are passed by pointed by default and are not always easy to clone especially as they may have circular references. You would be better suited with a different choice of data structures.

For those providing solutions to shallow copy the easier way is this:

 $b = (array)$a;

For deep copies I do not recommend this solution:

$nuarr = json_decode(json_encode($array));

This is for a deep copy. It only supports a subset of PHP types and will swap objects to array or arrays to objects which might not be what you want as well as potentially corrupting binary values and so on.

If you make a manual recursive function for deep copies the memory usage will be much less afterwards for scalar values and keys so using json or any serializer an impact beyond its point of execution.

It may be better to use unserialize(serialize($a)) for deep copies if performance is not a concern which has wider support for things such as objects though I would not be surprised if it breaks for circular references and several other unusual things.

array_merge_recursive or array_walk_recursive can also be used for arrays.

You can easily create your own recursive function that uses is_object and is_array to choose the appropriate means of copying.

回答11:

For PHP 5 and above one can use ArrayObject cunstructur to clone an array like the following:

$myArray = array(1, 2, 3);
$clonedArray = new ArrayObject($myArray);

回答12:

If you have multidimensional array or array composed of both objects and other values you can use this method:

$cloned = Arr::clone($array);

from that library.

来源：https://stackoverflow.com/questions/6418903/how-to-clone-an-array-of-objects-in-php

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arrays

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