cin

cin.ignore(numeric_limits<streamsize>::max(), '\n')

坚强是说给别人听的谎言 提交于 2019-11-30 11:17:03
问题 What does this particular line cin.ignore(numeric_limits<streamsize>::max(), '\n') , meant in C++ programming? Does this actually ignore then last input from the user? 回答1: This line ignores the rest of the current line, up to '\n' or EOF - whichever comes first: '\n' sets the delimiter, i.e. the character after which cin stops ignoring numeric_limits<streamsize>::max() sets the maximum number of characters to ignore. Since this is the upper limit on the size of a stream, you are effectively

cin.ignore(numeric_limits<streamsize>::max(), '\\n')

◇◆丶佛笑我妖孽 提交于 2019-11-30 01:48:54
What does this particular line cin.ignore(numeric_limits<streamsize>::max(), '\n') , meant in C++ programming? Does this actually ignore then last input from the user? This line ignores the rest of the current line, up to '\n' or EOF - whichever comes first: '\n' sets the delimiter, i.e. the character after which cin stops ignoring numeric_limits<streamsize>::max() sets the maximum number of characters to ignore. Since this is the upper limit on the size of a stream, you are effectively telling cin that there is no limit to the number of characters to ignore. cin.ignore(numeric_limits <

编写一段程序,用cin读入一组字符串并把它们存入一个vector对象并输出

蹲街弑〆低调 提交于 2019-11-30 00:50:54
编写一段程序,用cin读入一组字符串并把它们存入一个vector对象 string word; vector<string> text; // 空vector对象 while (cin >> word) { text.push_back(word); // 把word添加到text后面 } cout << "vector添加元素后为:" << endl; for (int i = 0; i < text.size(); i++) { cout << text[i] << " "; } cout << endl; 来源: CSDN 作者: 支离破碎的梦灬 链接: https://blog.csdn.net/weixin_43964833/article/details/103246356

Cin.Ignore() is not working

末鹿安然 提交于 2019-11-29 17:14:00
Here I have a code: cout << "Press Enter To Exit..."; cin.ignore(); this program will execute and will wait till you press enter and then it will exit. now see this code: int m; cin >> m; cout << "Press Enter To Exit..."; cin.ignore(); this time after entering a number for saving in "m" the program will exit without waiting for cin.ignore command which waits for pressing enter. I mean if you use cin command before cin.ignore, the cin.ignore command will skip. why? and what should I do for fixing it? Use this. std::cin.sync(); std::cin.get(); cin.ignore() basically clears any input left in

Avoiding infinite loop when a char is enter in place of int

蹲街弑〆低调 提交于 2019-11-29 14:45:25
I'm doing a Banking System project and need to make sure that every input is valid(program has to be robust). If invalid input is given then user has to enter again. But when i have a variable of int type and user enters char type an infinite loop begins. For example: int i; cin>>i; If user enters a char infinite loop starts. How can i avoid it and ask user for an input again? Thanks Here is another approach that might help; first writing to std::string and then going over all elements in the string checking if they're digit. Using header <cctype> for isdigit() and <cstdlib> for std::atoi ,

加速C++ cin,cout的速度

这一生的挚爱 提交于 2019-11-29 14:32:45
用以下两行代码: ios::sync_with_stdio(false); //加速 cin.tie(0); 首先sync_ with_ stdio(false)是为了打断iostream输入输出到缓存,可以节约很多时间,使之与scanf相差无几。 tie是将两个stream绑定的函数,空参数的话返回当前的输出指针,即tie(0)与tie(nullptr)来解决cin与cout的绑定。 来源: https://www.cnblogs.com/Bella2017/p/11519670.html

Why doesn't std::noskipws work, or what is it supposed to do?

会有一股神秘感。 提交于 2019-11-29 13:27:47
First off my understanding is that cin >> std::noskipws >> str; should stick a whole line from cin like "i have spaces" into str . However this only puts "i" into str . This could be a false assumption in which case what does std::noskipws do? I know there is a function std::getline and that does work but simply for educational purposes I decided I would try to get std::noskipws to work for me. I have tried in the past and it just never works so I normally move on and use std::getline . What I think I have found so far is that std::noskipws technically just unsets std::skipws which internally

C++ cin whitespace question

北城以北 提交于 2019-11-29 12:56:28
Programming novice here. I'm trying to allow a user to enter their name, firstName middleName lastName on one line in the console (ex. "John Jane Doe"). I want to make the middleName optional. So if the user enters "John Doe" it only saves the first and last name strings. If the user enters "John Jane Doe" it will save all three. I was going to use this: cin >> firstName >> middleName >> lastName; then I realized that if the user chooses to omit their middle name and enters "John Doe" the console will just wait for the user to enter a third string... I know I could accomplish this with one

Best way to read binary file c++ though input redirection

时光总嘲笑我的痴心妄想 提交于 2019-11-29 12:06:47
I am trying to read a large binary file thought input redirection ( stdin ) at runtime, and stdin is mandatory. ./a.out < input.bin So far I have used fgets. But fgets skips blanks and newline. I want to include both. My currentBuffersize could dynamically vary. FILE * inputFileStream = stdin; int currentPos = INIT_BUFFER_SIZE; int currentBufferSize = 24; // opt unsigned short int count = 0; // As Max number of packets 30,000/65,536 while (!feof(inputFileStream)) { char buf[INIT_BUFFER_SIZE]; // size of byte fgets(buf, sizeof(buf), inputFileStream); cout<<buf; cout<<endl; } Thanks in advance.

difference between cin.get() and cin.getline()

两盒软妹~` 提交于 2019-11-29 10:54:51
I am new to programming, and I have some questions on get() and getline() functions in C++. My understanding for the two functions: The getline() function reads a whole line, and using the newline character transmitted by the Enter key to mark the end of input. The get() function is much like getline() but rather than read and discard the newline character, get() leaves that character in the input queue. The book(C++ Primer Plus) that I am reading is suggesting using get() over getline() . My confusion is that isn't getline() safer than get() since it makes sure to end line with '\n' . On the