cin

while (!correct) { cout << "Please enter an angle value => "; cin >> value; //request user to input a value if(cin.fail()) // LINE 7 { cin.clear(); // LINE 9 while(cin.get() != '\n'); // LINE 10 textcolor(WHITE); cout << "Please enter a valid value. "<< endl; correct = false; } else { cin.ignore(); // LINE 18 correct =true; } } Hi, this is part of the code that I have written. The purpose of this code is to restrict users to input numbers like 10,10.00 etc, if they input values like (abc,!$@,etc...) the code will request users to reenter the values. In order to perform this function( restrict

My application is a GUI app that has helpful (though optional) information through the terminal (via cout). In Windows I either have a console appear (by compiling as a console app, or allocating it dynamically) or I don't. My intention is to make use of the console IF it is being run from the console, but ignore the console completely if it was not. (Essentially what happens in Linux and OS X). I do not wish to redirect to a file (and in the case of using cin, this is not a viable solution anyway). Is there a way to attach a GUI app in Windows to the console it is run from, if and only if it

We know input function or operator (cin, scanf,gets….etc) wait to take input form user & this time has no limit. Now, I will ask a question & user give the answer, till now there no problem but my problem is “user has a time(may 30 or 40 sec) to give the input, if he fail then input statement will automatically deactivated & execute next statement.” I think you get my problem. Then please help me in this situation. It will be better if someone give me some really working example code. I use codebolck 12.11 in windows 7. An approach for *IX'ish systems (including Cygwin on windows): You could

New to C++. Having issues correctly looping while handling errors. I am trying to check if user input is an integer, and is positive. do{ cout << "Please enter an integer."; cin >> n; if (cin.good()) { if (n < 0) {cout << "Negative.";} else {cout << "Positive.";} } else { cout << "Not an integer."; cin.clear(); cin.ignore(); } }while (!cin.good() || n < 0); cout << "\ndone."; When a non-integer is entered, the loop breaks. I feel like I am misunderstanding the inherent usage of cin.clear() and cin.ignore() and the status of cin during this loop. If I remove the cin.ignore() , the loop becomes

So I'm trying to read input like this from the standard input (using cin ): Adam English 85 Charlie Math 76 Erica History 82 Richard Science 90 My goal is to eventually store each data piece in its own cell in a data structure I have created, so basically I want to parse the input so each piece of data is individual. Since each row of input is inputted by the user one at a time, each time I get an entire row of input that I need to parse. Currently I am trying something like this: stringstream ss; getline(cin, ss); string name; string course; string grade; ss >> name >> course >> grade; The

I have these 2 codes: char a[256]; cin>>a; cout<<a; and char a[256]; cin.get(a,256);cin.get(); cout<<a; and maybe, relative to the second one without cin.get(); char a[256]; cin.get(a,256); cout<<a; My question is (first one) : for a char array, what should i use? cin or cin.get()? And why should i use cin.get(); with no parameter after my char initialisation? And my second question is: my c++ teacher taught me to use every time cin.get() for initialisation chars and AFTER every initialisation char array or int array or just int or whatever, to again put cin.get(); after it. That's what i

#include <iostream> #include <string> using namespace std; int main () { string str; int age; cout << "Please enter age: "; cin>>age; cout << "Please enter full name: "; getline (cin,str); cout << "Thank you, " << str << ".\n"; } Why function getline() not work when I using uperator >> to input integer ? What is better use for int input ? You still have a newline in the stream after cin>>age; , which is giving you an empty string for the name. You could solve it by just adding another getline() call after getting the age and throwing away the result. Another options is to call cin.ignore(BIG

I'm trying to get a line as input from the command line. My problem is that I'm not getting the whole line, but it's being tokenized by space. So if I entered something such as "I like Math a lot" instead of getting "you enterend: I like Math a lot" I get the follwoing: EDITING MODE: Enter a command i like Math a lot you entered i EDITING MODE: Enter a command you entered like EDITING MODE: Enter a command you entered Math EDITING MODE: Enter a command you entered a EDITING MODE: Enter a command you entered lot void enterEditingMode(){ editingMode = TRUE; static string CMD = "\nEDITING MODE:

More of a curiosity question than anything else, but is it actually possible to pass whatever goes through cin to a function without having to waste a variable? You can easily define a wrapper function to do this. template<class T> T get(std::istream& is){ T result; is >> result; return result; } Any decent compiler will use NRVO to eliminate the copy. You can use it like this f(get<int>(std::cin)); Make sure not to use it multiple times in one statement though. The order of the stream operations is unspecified if you do something like this. f(get<int>(std::cin),get<int>(std::cin)); You could

I'm writing a program that prompts the user for: Size of array Values to be put into the array First part is fine, I create a dynamically allocated array (required) and make it the size the user wants. I'm stuck on the next part. The user is expected to enter in a series of ints separated by commas such as: 1,2,3,4,5 How do I take in those ints and put them into my dynamically allocated array? I read that by default cin takes in integers separated by whitespace, can I change this to commas? Please explain in the simplest manner possible, I am a beginner to programming (sorry!) EDIT: TY so much