cin

I'm creating a simple console application in C++ that gets string and char inputs from the user. To make things simple, I would like to use the string and char data types to pass input from cin to. To get string inputs, I'm using the getline method: string var; cin.ignore(); //I used ignore() because it prevents skipping a line after using cin >> var getline(cin, var); To get char inputs, I'm using the cin >> var method: char var; cin >> var; This works fine for the most part. However, when I enter a string using getline , it ignores the first character of my string. Is it possible to use

cin空格截断 getline(cin,s) 换行结束 。。。。太愚蠢了 来源： https://www.cnblogs.com/lqerio/p/11674968.html

The program below shows a 'int' value being entered and being output at the same time. However, when I entered a character, it goes into an infinite loop displaying the previous 'int' value entered. How can I avoid a character being entered? #include<iostream> using namespace std; int main(){ int n; while(n!=0){ cin>>n; cout<<n<<endl; } return 0; } Reason for Infinite loop: cin goes into a failed state and that makes it ignore further calls to it, till the error flag and buffer are reset. cin.clear(); cin.ignore(100, '\n'); //100 --> asks cin to discard 100 characters from the input stream.

I would like to input a string of indefinite length to a char * variable using cin; I can do this: char * tmp = "My string"; cout << tmp << endl; system("pause"); It works perfectly. But I fail to do this: char * tmp cin >> tmp; Could you give me a hing what's wrong" Well, you havn't created an object for the char* to point to. char* tmp = new char[MAX_LENGTH]; should make it work better (you have to define MAX_LENGTH). Another way to do this is: std::string strtmp; cin >> strtmp; const char* tmp = strtmp.c_str(); This method would mean that you need not use new . Couple of issues: char * tmp

My program: class test { int k; public: void changeval(int i){k=i;} }; int main() { test obj; int i; cin>>i; obj.changeval(i); return 0; } Is there any way, by which i can directly pass input from the user as an argument to the function changeval(int), without even initializing value to i?? I mean, i don't want to declare a variable just to pass value to a function. Is there any way i can avoid it? If yes, can I use it for constructors also? Thanks. Nope. Now, you could put this into a function: int readInt(std::istream& stream) { int i; stream >> i; // Cross your fingers this doesn't fail