cin.ignore(numeric_limits<streamsize>::max(), '\n')

问题

What does this particular line cin.ignore(numeric_limits<streamsize>::max(), '\n'), meant in C++ programming? Does this actually ignore then last input from the user?

回答1:

This line ignores the rest of the current line, up to '\n' or EOF - whichever comes first:

• '\n' sets the delimiter, i.e. the character after which cin stops ignoring
• numeric_limits<streamsize>::max() sets the maximum number of characters to ignore. Since this is the upper limit on the size of a stream, you are effectively telling cin that there is no limit to the number of characters to ignore.

回答2:

cin.ignore(numeric_limits < streamsize > ::max(), '\n');

Here, the \n acts as a delimiter.... that is the point upto which the code has to be ignored(as "\n" in this perticular case). And max() defines that there is no limit for how much can be ignored, the spaces, tabs have to be ignored untill the line ends.

来源：https://stackoverflow.com/questions/25020129/cin-ignorenumeric-limitsstreamsizemax-n