any

问题 I would like to use JQ to modify the following JSON input: { "rows": [ { "fields": [ { "name": "id", "value": "k1" }, { "name": "val", "value": "2340378b211aa3d8f2d7607cbddce883b87b191d0425736641e3d308ea329718" }, { "name": "Encoding", "value": "hex" } ] }, { "fields": [ { "name": "id", "value": "k2" }, { "name": "val", "value": "2340378b211aa3d8f2d7607cbddce883b87b191d0425736641e3d308ea329718" }, { "name": "Encoding", "value": "hex" } ] } ] } so that the "hex" value of the "value" field with

问题 I would like to use JQ to modify the following JSON input: { "rows": [ { "fields": [ { "name": "id", "value": "k1" }, { "name": "val", "value": "2340378b211aa3d8f2d7607cbddce883b87b191d0425736641e3d308ea329718" }, { "name": "Encoding", "value": "hex" } ] }, { "fields": [ { "name": "id", "value": "k2" }, { "name": "val", "value": "2340378b211aa3d8f2d7607cbddce883b87b191d0425736641e3d308ea329718" }, { "name": "Encoding", "value": "hex" } ] } ] } so that the "hex" value of the "value" field with

问题 What is the difference between IN and ANY operators in SQL ? 回答1: SQL> SQL> -- Use the ANY operator in a WHERE clause to compare a value with any of the values in a list. SQL> SQL> -- You must place an =, <>, <, >, <=, or >= operator before ANY. SQL> SELECT * 2 FROM employee 3 WHERE salary > ANY (2000, 3000, 4000); For In Operator SQL> -- Use the IN operator in a WHERE clause to compare a value with any of the values in a list. SQL> SELECT * 2 FROM employee 3 WHERE salary IN (2000, 3000, 4000

问题 I read swift documentation in apple site. There is a function swapTwoValues, which swaps two any given values func swapTwoValues1<T>(_ a: inout T, _ b: inout T) { let temporaryA = a a = b b = temporaryA } Now I want to write similar function but instead of using T generic type I want to use Any func swapTwoValues2(_ a: inout Any, _ b: inout Any) { let temporaryA = a a = b b = temporaryA } to call this functions I write var a = 5 var b = 9 swapTwoValues1(&a, &b) swapTwoValues2(&a, &b) I have

问题 (I expect this has already been asked/answered. If so, sorry, I'm failing to locate the answer.) Let's say I have 6 vectors. How can I quickly check whether any element for each vector is equal to any element of all the other vectors? I know I could do the following, and it feels really cumbersome/pre-historic/error-prone: any(vec1 %in% vec2, vec1 %in% vec3, vec1 %in% vec4, vec1 %in% vec5, vec1 %in% vec6, vec2 %in% vec3, vec2 %in% vec4, vec2 %in% vec5, vec2 %in% vec6, vec3 %in% vec4, vec3 %in

问题 (I expect this has already been asked/answered. If so, sorry, I'm failing to locate the answer.) Let's say I have 6 vectors. How can I quickly check whether any element for each vector is equal to any element of all the other vectors? I know I could do the following, and it feels really cumbersome/pre-historic/error-prone: any(vec1 %in% vec2, vec1 %in% vec3, vec1 %in% vec4, vec1 %in% vec5, vec1 %in% vec6, vec2 %in% vec3, vec2 %in% vec4, vec2 %in% vec5, vec2 %in% vec6, vec3 %in% vec4, vec3 %in

问题 (I expect this has already been asked/answered. If so, sorry, I'm failing to locate the answer.) Let's say I have 6 vectors. How can I quickly check whether any element for each vector is equal to any element of all the other vectors? I know I could do the following, and it feels really cumbersome/pre-historic/error-prone: any(vec1 %in% vec2, vec1 %in% vec3, vec1 %in% vec4, vec1 %in% vec5, vec1 %in% vec6, vec2 %in% vec3, vec2 %in% vec4, vec2 %in% vec5, vec2 %in% vec6, vec3 %in% vec4, vec3 %in

问题 I have set (not list) of strings (words). It is a big one. (It's ripped out of images with openCV and tesseract so there's no reliable way to predict its contents.) At some point of working with this list I need to find out if it contains at least one word that begins with part I'm currently processing. So it's like (NOT an actual code): if exists(word.startswith(word_part) in word_set) then continue else break There is a very good answer on how to find all strings in list that start with

问题 I have set (not list) of strings (words). It is a big one. (It's ripped out of images with openCV and tesseract so there's no reliable way to predict its contents.) At some point of working with this list I need to find out if it contains at least one word that begins with part I'm currently processing. So it's like (NOT an actual code): if exists(word.startswith(word_part) in word_set) then continue else break There is a very good answer on how to find all strings in list that start with

问题 I am trying to remove duplicate data from my database. I found a nice example on here of how to do this on an oracle database. The bottom query from that answer (only selecting the duplicate rows) works in MySQL, but the delete query (see below) does not... "DELETE FROM studios as a WHERE a.id > ANY (SELECT b.id FROM studios as b WHERE a.name = b.name AND a.email = b.email )" The error I get is: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server