any | 易学教程

EFCore 3.1 - Exists query via Any; Query cannot be translated

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问题 We're using EFCore 3.1 and trying to build a query using Exists by means of .Any() which spans 2 properties. var selectionCriteria = someHugeList.Select(sh => new { sh.Id, sh.StatusCode }).ToList() var resultsQry = _myContext.SomeClass .Include(sc => sc.DetailRecords) .Where(sc => selectionCriteria.Any(crit => crit.Id == sc.Id && crit.StatusCode == sc.StatusCode)); var results = await resultsQry.ToListAsync() When running this query (even with a small amount (5 items) of selection criteria

SQLite syntax for operator “ANY”

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问题 I'm trying execute this query in SQLite: SELECT * FROM customers WHERE rating = ANY (SELECT rating FROM customers WHERE city = 'Rome'); But received this error: Query Error: near "SELECT": syntax error Unable to execute statement If I replace rating = ANY to rating IN , everything works fine. Can someone show me how ANY statement works in SQLite and what I am doing wrong? 回答1: AFAIK, SQLite doesn't have an ANY operator. You could, however, use the IN operator to get the required functionality

SQLite syntax for operator “ANY”

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Lifetime issue when using the Any trait to get references to structs containing references

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问题 I ran into a lifetime problem with a little game. The below code represents a very boiled down version of the update loop. I need the container mutable reference to get references to other game objects or to create new ones or trigger a functionality. For that reason, I need the Any trait to be able to cast the trait to a struct, so in my GameObj trait I added an as_any method, but this resulted in a lifetime issue. use std::any::Any; trait GameObj<'a> { fn as_any<'b>(&'b self) -> &'b (dyn

Lifetime issue when using the Any trait to get references to structs containing references

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Python: Lazy Function Evaluation in any() / all()

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问题 Logical operators in Python are lazy. With the following definition: def func(s): print(s) return True calling the or operator >>> func('s') or func('t') 's' only evaluates the first function call, because or recognizes that the expression evaluates to True , irregardless of the return value of the second function call. and does behave analogously. However, when using any() (analogously: all() ) in the following way: >>> any([func('s'), func('t')]) 's' 't' all function calls are evaluated,

Difference between CREATE TABLE and CREATE ANY TABLE privileges

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来源： https://stackoverflow.com/questions/54494066/difference-between-create-table-and-create-any-table-privileges

Good way to get any value from a Java Set?

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来源： https://stackoverflow.com/questions/13692700/good-way-to-get-any-value-from-a-java-set

Good way to get any value from a Java Set?

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来源： https://stackoverflow.com/questions/13692700/good-way-to-get-any-value-from-a-java-set

swift类型转换is和as

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Swift中类型转换使用 is 和 as 操作符。使用这两个操作符可以检查值的类型或者转换他的类型一、类型检查 class Animal: NSObject { var name: String! init(name: String) { self.name = name } } class Dog: Animal { var color: UIColor! init(name: String,color: UIColor) { self.color = color super.init(name: name) } } class Cat: Animal { var weight: Float! init(name: String,weight: Float) { self.weight = weight super.init(name: name) } } let animals = [Dog.init(name: "tiger", color: UIColor.yellow), Dog.init(name: "wangcai", color: UIColor.black), Cat.init(name: "hellokitty", weight: 10.0)] 如上创建三个类： Animal，Dog，Cat ，其中Cat和Dog继承与Animal 。创建了一个容器