Removing Duplicate Elements from List of Lists in Prolog

匿名 (未验证) 提交于 2019-12-03 01:41:02

问题:

I am trying to work out how to remove duplicate elements in a list of lists in Prolog.

E.g:
input: [[1,2,3],[5,6],[3,4],[1,7]]

expected output: [[1,2,3],[5,6],[4],[7]]

I know I can use the predicate sort/2 to remove duplicates in a single list, but how do I get it to work across multiple lists?

回答1:

Here is my attempt. Hope you've made some attempts to solve it and learn from this...Anyway if you still didn't come up with anything take a look at the following code:

 remove_dupl(InL, OutL):- remove_dupl(InL, [], OutL1),remove_empty(OutL1,OutL).  remove_dupl([],_,[]). remove_dupl([H|T],L,[[H1]|T2]):-               H=[H1], \+member(H1,L),                remove_dupl(T,[H1|L],T2). remove_dupl([H|T],L,[[H1|T2]|T3]):-                H=[H1|T1], \+member(H1,L),                remove_dupl([T1|T],[H1|L],[T2|T3]). remove_dupl([H|T],L,T2):-                H=[H1|T1], member(H1,L),                remove_dupl([T1|T],L,T2). remove_dupl([H|T],L,[[]|T2]):-                H=[H1], member(H1,L),                remove_dupl(T,L,T2).  remove_empty([],[]). remove_empty([[]|T],T1):-remove_empty(T,T1). remove_empty([[H|T]|T1],[[H|T]|T2]):-remove_empty(T1,T2).

Maybe not the most efficient solution. Example:

?- remove_dupl([[1,2,3],[5,6],[3,4],[1,7]],L). L = [[1, 2, 3], [5, 6], [4], [7]] ; false.


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