Multiple arguments in stringWithFormat: “n$” positional specifiers

二次信任 提交于 2019-11-29 17:32:16

I implemented a custom method to achieve expected output. This method can handle missing positional specifier. This method will only work for format containing positional specifier %n$@.

/**
 @param format String format with positional specifier
 @param arg Array of arguments to replace positional specifier in format
 @return Formatted output string
 */
+(NSString*)stringWithPositionalSpecifierFormat:(NSString*)format arguments:(NSArray*)arg
{
    static NSString *pattern = @"%\\d\\$@";

    NSError *error;
    NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:pattern options:NSRegularExpressionCaseInsensitive error:&error];

    NSMutableString *mString = [[NSMutableString alloc] initWithString:format];
    NSArray *allMatches = [regex matchesInString:format options:0 range:NSMakeRange(0, [format length])];
    if (!error && allMatches>0)
    {
        for (NSTextCheckingResult *aMatch in allMatches)
        {
            NSRange matchRange = [aMatch range];
            NSString *argPlaceholder = [format substringWithRange:matchRange];
            NSMutableString *position = [argPlaceholder mutableCopy];
            [position replaceOccurrencesOfString:@"%" withString:@"" options:NSCaseInsensitiveSearch range:NSMakeRange(0, [position length])];
            [position replaceOccurrencesOfString:@"$@" withString:@"" options:NSCaseInsensitiveSearch range:NSMakeRange(0, [position length])];
            int index = position.intValue;
            //Replace with argument
            [mString replaceOccurrencesOfString:argPlaceholder withString:arg[index-1] options:NSCaseInsensitiveSearch range:NSMakeRange(0, [mString length])];
        }
    }
    return mString;
}
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