问题
What regular expression using java could be used to filter out dashes '-' and open close round brackets from a string representing phone numbers...
so that (234) 887-9999 should give 2348879999 and similarly 234-887-9999 should give 2348879999.
Thanks,
回答1:
phoneNumber.replaceAll("[\\s\\-()]", "");
The regular expression defines a character class consisting of any whitespace character (\s
, which is escaped as \\s
because we're passing in a String), a dash (escaped because a dash means something special in the context of character classes), and parentheses.
See String.replaceAll(String, String).
EDIT
Per gunslinger47:
phoneNumber.replaceAll("\\D", "");
Replaces any non-digit with an empty string.
回答2:
public static String getMeMyNumber(String number, String countryCode)
{
String out = number.replaceAll("[^0-9\\+]", "") //remove all the non numbers (brackets dashes spaces etc.) except the + signs
.replaceAll("(^[1-9].+)", countryCode+"$1") //if the number is starting with no zero and +, its a local number. prepend cc
.replaceAll("(.)(\\++)(.)", "$1$3") //if there are left out +'s in the middle by mistake, remove them
.replaceAll("(^0{2}|^\\+)(.+)", "$2") //make 00XXX... numbers and +XXXXX.. numbers into XXXX...
.replaceAll("^0([1-9])", countryCode+"$1"); //make 0XXXXXXX numbers into CCXXXXXXXX numbers
return out;
}
来源:https://stackoverflow.com/questions/2717421/remove-dash-from-a-phone-number