How to match all numerical characters and some single characters using regex

问题

How can I match all numbers along with specific characters in a String using regex? I have this so far

if (!s.matches("[0-9]+")) return false;

I don't understand much regex, but this matches all characters from 0-9 and now I need to be able to match other specific characters, for example "/", ":", "$"

回答1:

You can use this regex by including those symbols in a character class:

s.matches("[0-9$/:]+")

Read more about character class

回答2:

You can add the other characters that you need to match to the end of the character group, like this:

if (!s.matches("[0-9/:$]+")) return false;

You need to be careful about several things:

• If ^ is among the characters, it must not be the first one of the group
• If - is among the characters, it must be the last one in the group
• If ] is among the characters, it needs to be escaped for regex and for Java, e.g. [\\]]
• If \ is among the characters, it needs to be escaped for regex and for Java, e.g. [\\\\]

回答3:

Regex:

String regex = "\\d/:$+";

来源：https://stackoverflow.com/questions/20952787/how-to-match-all-numerical-characters-and-some-single-characters-using-regex