java.lang.NumberFormatException while executing in France machine

问题

In below code while parsing the value sometimes i am facing NumberFormat Exception in France machine.

double txPower;
DecimalFormat df = new DecimalFormat("##.##");

txPower = txPower + getDeltaP();
log.info("txpower value is -- "+txPower);
txPower = Double.parseDouble(df.format(txPower));


protected double getDeltaP() 
{
    return isNewChannelAddition ? apaConfig.deltaPadd : apaConfig.deltaPtune;
}

logs:

txpower value is -- -7.9
java.lang.NumberFormatException: For input string: "-7,9"

回答1:

I suggest to use the decimal separator configured as default for your locale.

new DecimalFormatSymbols(Locale.getDefault(Locale.Category.FORMA‌T)).getDecimalSepara‌tor();

回答2:

You have to ways to solve your problem :

One, you can use replace(",", ".") like this :

txPower = Double.parseDouble(df.format(txPower).replace(",", "."));

Two, you can use the local for the DecimalFormat :

DecimalFormat df = (DecimalFormat) DecimalFormat.getInstance();
df.applyLocalizedPattern("##.##");
txPower = txPower + getDeltaP();
txPower = Double.parseDouble(df.format(txPower));

回答3:

You can also call something like this String.format("%.2f", -7.9)

回答4:

Double.parseDouble doesn't support locale-specific decimal points (see the doc here). Try using your DecimalFormat to parse instead:

txPower = df.parse(df.format(txPower)).doubleValue();

Having said that, I must ask what you are hoping to gain by to turning the double value txPower into a String, parsing the string into a double and putting the result back into txPower?

来源：https://stackoverflow.com/questions/44541638/java-lang-numberformatexception-while-executing-in-france-machine

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