rounded to the nearest 10's place in c#

问题

I want to The numbers are being rounded to the nearest 10's place. For example, a number like 17.3 is being rounded to 20.0. and want to be allow three significant digits. Meaning for round to the nearest tenth of a percent as the last step of the process.

Sample :

    the number is 17.3 ,i want round to 20 ,

    and this number is 13.3 , i want round to 10 ?

How can i do this ?

回答1:

Chris Charabaruk gives you your desired answer here

To get to the core, here is his solution as an extension method:

public static class ExtensionMethods
{
    public static int RoundOff (this int i)
    {
        return ((int)Math.Round(i / 10.0)) * 10;
    }
}

int roundedNumber = 236.RoundOff(); // returns 240
int roundedNumber2 = 11.RoundOff(); // returns 10

//edit: This method only works for int values. You'd have to edit this method to your liking. f.e.: public static class ExtensionMethods

{
    public static double RoundOff (this double i)
    {
       return (Math.Round(i / 10.0)) * 10;
    }
}

/edit2: As corak stated you should/could use

Math.Round(value / 10, MidpointRounding.AwayFromZero) * 10

回答2:

Other answers are correct also, but here's how you'd do it without Math.Round:

((int)((17.3 + 5) / 10)) * 10 // = 20
((int)((13.3 + 5) / 10)) * 10 // = 10
((int)((15.0 + 5) / 10)) * 10 // = 20

回答3:

Try this-

double d1 = 17.3;
int rounded1 = ((int)Math.Round(d/10.0)) * 10; // Output is 20

double d2 = 13.3;
int rounded2 = ((int)Math.Round(d/10.0)) * 10; // Output is 10

回答4:

double Num = 16.6;
int intRoundNum = (Convert.ToInt32(Math.Round(Num / 10)) * 10);
Console.WriteLine(intRoundNum);

来源：https://stackoverflow.com/questions/18349844/rounded-to-the-nearest-10s-place-in-c-sharp

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ASP.NET

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