问题
Please see these simple commands:
$ echo $tmp
UY\U[_
$ echo "a" | sed "s|a|${tmp}|g"
UY[_
The \U is eaten. Other backslashes won't survive either.
How can I make the above command work as expected?
回答1:
If it's only backslash that is "eaten" by sed and escaping just that is enough, then try:
echo "a" | sed "s|a|${tmp//\\/\\\\}|g"
Confusing enough for you? \\ represents a single \ since it needs to be escaped in the shell too.
The inital // is similar to the g modifier in s/foo/bar/g, if you only want the first occurring pattern to be replaced, skip it.
The docs about ${parameter/pattern/string} is available here: http://www.gnu.org/s/bash/manual/bash.html#Shell-Parameter-Expansion
Edit: Depending on what you want to do, you might be better of not using sed for this actually.
$ tmp="UY\U[_"
$ in="a"
$ echo ${in//a/$tmp}
UY\U[_
回答2:
You could reparse $tmp itself through sed
echo "a" | sed "s|a|$(echo ${tmp} | sed 's|\\|\\\\|g')|g"
来源：https://stackoverflow.com/questions/7512309/how-can-i-insert-a-variable-containing-a-backslash-in-sed