sed

问题 I want to remove negative words form sentence using bash script . The negative words that i meant it : [dull,boring,annoying,bad] My file text text.txt contains this sentence : These dull boring cards are part of a chaotic board game ,and bad for people I'm using this script array=( dull boring annoying bad ) for i in "${array[@]}" do cat $p | sed -e 's/\<$i\>//g' done < my_text.txt But I got the following wrong result: These boring cards are part of a chaotic board game ,and bad for people

问题 I was forced to calculate the string length in sed . The string is always a nonempty sequence of a 's. sed -n ':c /a/! be; s/^a/1/; s/0a/1/; s/1a/2/; s/2a/3/; s/3a/4/; s/4a/5/; s/5a/6/; s/6a/7/; s/7a/8/; s/8a/9/; s/9a/a0/; /a/ bc; :e p' It's quite long :) So now I wonder if it is possible to rewrite this script more concisely using the y or other sed command? I know that it is better to use awk or another tool. However, this is not a question here. Note that the sed script basically simulates

问题 I was forced to calculate the string length in sed . The string is always a nonempty sequence of a 's. sed -n ':c /a/! be; s/^a/1/; s/0a/1/; s/1a/2/; s/2a/3/; s/3a/4/; s/4a/5/; s/5a/6/; s/6a/7/; s/7a/8/; s/8a/9/; s/9a/a0/; /a/ bc; :e p' It's quite long :) So now I wonder if it is possible to rewrite this script more concisely using the y or other sed command? I know that it is better to use awk or another tool. However, this is not a question here. Note that the sed script basically simulates

问题 Need to print lines after the last match to the end of file. The number of matches could be anything and not definite. I have some text as shown below. MARKER aaa bbb ccc MARKER ddd eee fff MARKER ggg hhh iii MARKER jjj kkk lll Output desired is jjj kkk lll Do I use awk with RS and FS to get the desired output? 回答1: You can actually do it with awk (gawk) without using any pipe. $ awk -v RS='(^|\n)MARKER\n' 'END{printf "%s", $0}' file jjj kkk lll Explanations: You define your record separator

问题 So I have the following sed one liner: sed -e '/^S|/d' -e '/^T|/d' -e '/^#D=/d' -e '/^##/d' -e 's/H|/,H|/g' -e 's/Q|/,,Q|/g' -e '1 i\,,,' sample_1.txt > sample_2.txt I have many lines that start with either: S| T| #D= ## H| Q| The idea is to not copy the lines starting with one of the first fours and to replace H| (at the beginning of lines) by ,H| and Q| (at the beginning of lines) by ,,Q| But now I would need to: use the fastest way possible (internet suggests (m)awk is faster than sed)

问题 So I have the following sed one liner: sed -e '/^S|/d' -e '/^T|/d' -e '/^#D=/d' -e '/^##/d' -e 's/H|/,H|/g' -e 's/Q|/,,Q|/g' -e '1 i\,,,' sample_1.txt > sample_2.txt I have many lines that start with either: S| T| #D= ## H| Q| The idea is to not copy the lines starting with one of the first fours and to replace H| (at the beginning of lines) by ,H| and Q| (at the beginning of lines) by ,,Q| But now I would need to: use the fastest way possible (internet suggests (m)awk is faster than sed)

问题 for example, suppose I have logfile.txt which contains "Here is a sample text file" My pattern is "sample" How can I get the word next to sample in my logfile.txt. 回答1: Here is one way to do it with awk: $ awk '{for(i=1;i<=NF;i++)if($i=="sample")print $(i+1)}' file text Explained: $ awk '{ for(i=1;i<=NF;i++) # process every word if($i=="sample") # if word is sample print $(i+1) # print the next }' file and sed: $ sed -n 's/.* sample \([^ ]*\).*/\1/p' file text ie. after sample next space

问题 I'm trying to grab data from HTML output that looks like this: <strong>Target1NoSpaces</strong><span class="creator"> .... <strong>Target2 With Spaces</strong><span class="creator"> .... I'm using a pipe train to whittle down the data to the targets I'm trying to hit. Here's my approach so far: grep "/strong" output.html | awk '{print $1}' Grep on "/strong" to get the lines with the targets; that works fine. Pipe to 'awk '{print $1}'. That works in case #1 when the target has no spaces, but

问题 This question already has answers here : sed substitution with Bash variables (4 answers) Closed 5 years ago . I want to replace a line that says alpha = -pi/... with the correct calculated value in radians of the angle given ie variable n1 #!/bin/bash read -p "Angle in degrees : " n1 ## Convert angle to radians printf -v "n2" "%.0f" $(echo | bc | awk "BEGIN {print 180/$n1}") echo "$n1 Degrees = pi/$n2" printf -v "n3" "alpha = -pi/$n2;" echo "${n3}" cd /home/src/octave_scripts/makemesh_rot

问题 This is kind of a weird one. I have the following string: I have a variable called REDIRECT set to: https://working.${MYDOMAIN}/blah/blah . I need to replace the ${MYDOMAIN} with the actual value of the variable assigned to ${MYDOMAIN}. Not sure if bash or sed is best for this. I tried bash replace but couldn't get it to work, probably related to escaping the characters or something. Any help appreciated! 回答1: You may use this bash substitution: echo "${REDIRECT/\${MYDOMAIN\}/$MYDOMAIN}" or