问题
The problem I have is that I basically would like to find if there are any free subnets between a BGP aggregate-address (ex: 10.76.32.0 255.255.240.0) and all the network commands on the same router (ex: 10.76.32.0 255.255.255.0, 10.76.33.0 255.255.255.0)
In the above example 10.76.34.0 -> 10.76.47.255 would be free.
I'm thinking of tackling this problem by converting the IP addresses and subnet masks to binary and subtracting that way.
To keep it simple I will keep this example in decimal but doing this would leave me with the following problem: let's say I have a range from 1 to 250, I subtract from this a smaller range that goes from 20 to 23, I would like to end up with a range from 1 to 19 and 24 to 250.
Using the range command doesn't really give me the expected results and while I could possibly create a list with every item in the range and subtract another list with a sub-set of items, it seems to me that it might not be a good idea to have lists with possibly tens of thousands of elements.
Hunor
回答1:
If you are trying to create a "range" with a gap in it, i.e., with 1-9 and 24-250, you could try to use filterfalse (or ifilterfalse if you are using Python 2.X) from the itertools module, which takes as its arguments a predicate and a sequence, and returns elements of the sequence where the predicate returns False
. As an example, if you do:
from itertools import filterfalse
new_range = filterfalse(lambda x: 20 <= x <= 23, range(1,251))
new_range
will be an iterable containing the numbers 1-19, and 24-250, which can be used similarly to range()
:
for i in new_range:
do_things()
回答2:
The question has been asked long ago but I want to add numpy array
answer.
import numpy as np
aa=np.arange(1,251)
bb=np.concatenate((np.array(aa[aa<20]),np.array(aa[aa>23])))
print(bb)
output
array([ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13,
14, 15, 16, 17, 18, 19, 24, 25, 26, 27, 28, 29, 30,
31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43,
44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56,
57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69,
70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82,
83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95,
96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107, 108,
109, 110, 111, 112, 113, 114, 115, 116, 117, 118, 119, 120, 121,
122, 123, 124, 125, 126, 127, 128, 129, 130, 131, 132, 133, 134,
135, 136, 137, 138, 139, 140, 141, 142, 143, 144, 145, 146, 147,
148, 149, 150, 151, 152, 153, 154, 155, 156, 157, 158, 159, 160,
161, 162, 163, 164, 165, 166, 167, 168, 169, 170, 171, 172, 173,
174, 175, 176, 177, 178, 179, 180, 181, 182, 183, 184, 185, 186,
187, 188, 189, 190, 191, 192, 193, 194, 195, 196, 197, 198, 199,
200, 201, 202, 203, 204, 205, 206, 207, 208, 209, 210, 211, 212,
213, 214, 215, 216, 217, 218, 219, 220, 221, 222, 223, 224, 225,
226, 227, 228, 229, 230, 231, 232, 233, 234, 235, 236, 237, 238,
239, 240, 241, 242, 243, 244, 245, 246, 247, 248, 249, 250])
来源:https://stackoverflow.com/questions/40043103/python-subtracting-ranges-from-bigger-ranges