Create hash from array and frequency

问题

I have an array [1,2,4,5,4,7] and I want to find the frequency of each number and store it in a hash. I have this code, but it returns NoMethodError: undefined method '+' for nil:NilClass

def score( array )
  hash = {}
  array.each{|key| hash[key] += 1}
end

Desired output is

{1 => 1, 2 => 1, 4 => 2, 5 => 1, 7 => 1 }

回答1:

Do as below :

def score( array )
  hash = Hash.new(0)
  array.each{|key| hash[key] += 1}
  hash
end
score([1,2,4,5,4,7]) # => {1=>1, 2=>1, 4=>2, 5=>1, 7=>1}

Or more Rubyish using Enumerable#each_with_object:

def score( array )
  array.each_with_object(Hash.new(0)){|key,hash| hash[key] += 1}
end
score([1,2,4,5,4,7]) # => {1=>1, 2=>1, 4=>2, 5=>1, 7=>1}

The reason of why NoMethodError: undefined method '+' for nil:NilClass ?

hash = {} is an empty has,with default value as nil.nil is an instance of Nilclass,and NilClass doesn't have any instance method called #+. So you got NoMethodError.

Look at the Hash::new documentation :

new → new_hash
new(obj) → new_hash

Returns a new, empty hash. If this hash is subsequently accessed by a key that doesn’t correspond to a hash entry, the value returned depends on the style of new used to create the hash. In the first form, the access returns nil. If obj is specified, this single object will be used for all default values. If a block is specified, it will be called with the hash object and the key, and should return the default value. It is the block’s responsibility to store the value in the hash if required.

回答2:

In Ruby 2.4+:

def score(array)
  array.group_by(&:itself).transform_values!(&:size)
end

回答3:

Just use inject. This type of application is exactly what it is meant for. Something like:

a.inject(Hash.new(0)) {|hash,word| hash[word] += 1; hash }

回答4:

Love me some inject:

results = array.inject(Hash.new(0)) {|hash, arr_element| hash[arr_element] += 1; hash }

1.9.3p448 :082 > array = [1,2,4,5,4,7]
 => [1, 2, 4, 5, 4, 7] 
1.9.3p448 :083 > results = array.inject(Hash.new(0)) {|hash, arr_element| hash[arr_element] += 1; hash }
 => {1=>1, 2=>1, 4=>2, 5=>1, 7=>1}

回答5:

Here is a short option that uses the Hash array initializer

Hash[arr.uniq.map {|v| [v, arr.count(v)] }]

回答6:

Ruby 2.7 onwards will have the Enumerable#tally method that will solve this.

From the trunk documentation:

Tallys the collection. Returns a hash where the keys are the elements and the values are numbers of elements in the collection that correspond to the key.

["a", "b", "c", "b"].tally #=> {"a"=>1, "b"=>2, "c"=>1}

回答7:

The point here is that hash[1] doesn't exist (nil) when it first sees 1 in the array.

You need to initialize it somehow, and hash = Hash.new(0) is the easiest way. 0 is the initial value you want in this case.

回答8:

Or use the group by method:

arr = [1,2,4,5,4,7]

Hash[arr.group_by{|x|x}.map{|num,arr| [num, arr.size] }]

来源：https://stackoverflow.com/questions/19963001/create-hash-from-array-and-frequency

标签

ruby

arrays

hash