How to properly evaluate sage code from within a Python script

问题

I've been trying to evaluate a simple "integrate(x,x)" statement from within Python, by following the Sage instructions for importing Sage into Python. Here's my entire script:

    #!/usr/bin/env sage -python

from sage.all import *
def main():
    integrate(x,x)
    pass
main()

When I try to run it from the command line, I get this error thrown:

NameError: global name 'x' is not defined

I've tried adding var(x) into the script, global x, tried replacing integrate(x,x) with sage.integrate(x,x), but I can't seem to get it to work, I always get an error thrown.

The command I'm using is ./sage -python /Applications/path_to/script.py

I can't seem to understand what I'm doing wrong here.

Edit: I have a feeling it has something to do with the way I've "imported" sage. I have my a folder, let's call it folder 1, and inside of folder 1 is the "sage" folder and the "script.py"

I am thinking this because typing "sage." doesn't bring up any autocomplete options.

回答1:

The name x is not imported by import sage.all. To define a variable x, you need to issue a var statement, like thus

var('x')
integrate(x,x)

or, better,

x = SR.var('x')
integrate(x,x)

the second example does not automagically inject the name x in the global scope, so that you have to explicitly assign it to a variable.

回答2:

Here's what Sage does (see the file src/sage/all_cmdline.py):

from sage.all import *
from sage.calculus.predefined import x

If you put these lines in your Python file, then integrate(x,x) will work. (In fact, sage.calculus.predefined just defines x using the var function from sage.symbolic.ring; this just calls SR.var, as suggested in the other answer. But if you want to really imitate Sage's initialization process, these two lines are what you need.)

来源：https://stackoverflow.com/questions/24592346/how-to-properly-evaluate-sage-code-from-within-a-python-script

标签

python

sage

evaluate