PHP condition, if current page, then link is highlighted [closed]

问题

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Closed 6 years ago.

I have a webpage with a side bar that uses some css class. If the class = "active', then the link will be highlighted. I want to make it so that at any page, the script would check which link it's at, then decide which link to be highlighted. Below is where I'm at, but I really don't have a clue how to proceed, please point me in the right and better direction! If I have 20 links, this script would be way too long.... Thank you!

---

<?php






$arr = array(

'1' => '/about.php', 
'2'=> '/abt-history2.php',
'3' => '/abt-shop.php',
);

$host =  $_SERVER['REQUEST_URI'];


if($host == $arr['1']) 
{
    $class1 = "active";
}

else if ($host == $arr['2']) 
{
    $class2 = "active";
}

else if ($host == $arr['3']) 
{
    $class3 = "active";
}


 ?>






   <ul id="navigationSide">
      <div style="padding-left:20px; padding-bottom:10px; font-size:16px; font-weight:800; color:#777;">TITLE</div>
      <li><a href="<?php print $arr['1'];  ?>" class="<?php echo"$class1" ?>">AA</a></li>
      <li><a href="<?php print $arr['2'];  ?>" class="<?php echo"$class2" ?>">BB</a></li>
    </ul>
    <div style="padding:5px;"></div>
    <ul id="navigationSide">
      <div style="padding-left:20px; padding-bottom:10px;  font-size:16px; font-weight:800; color:#777;">TITLE2</div>
      <li><a href="<?php print $arr['3'];  ?>" class="<?php echo"$class3" ?>" >CC</a></li>

</ul>

回答1:

Ok, this is new, I removed all I had posted before, and this is what another answer. Since, $_SERVER['REQUEST_URI'] gets /Portal/TEST/file.php in my localhost, I have added /Portal/TEST/ in the script, you can remove it depending on the structure of your files.

<?php 
$arr = array(

'0' => '/Portal/TEST/about.php', 
'1'=> '/Portal/TEST/abt-history2.php',
'2' => '/Portal/TEST/abt-shop.php',
'3' => '/Portal/TEST/extra.php',
'3' => '/Portal/TEST/blaze.php',
);




 ?>


<h2>TITLE</h2>

<?php 

 for($i=0; $i< count($arr); $i++) {  



    if($_SERVER['REQUEST_URI'] == $arr[$i]) {

    $class = 'active';
 ?>


  <li><a href="<?php print $arr[$i];  ?>" class="<?php echo "$class".$i ?>"><?php echo $class ?>
</a></li>   <?php }else {
$class  = 'In active';

?>  
  <li><a href="<?php print $arr[$i];  ?>" class="<?php echo "$class".$i ?>"><?php echo $class ?>
</a></li> 

<?php
}

 }?>

回答2:

Try
  <?php
    $arr = array(

      '1' => 'about.php', 
      '2'=> 'abt-history.php',
      '3' => 'abt-shop.php',
    );


    foreach($arr as $key => $page){

      $class = "";

      $currentPage = $_SERVER['REQUEST_URI']; // check its value and get page name

      if($currentPage ==  $page){

       $class = 'class ="active"';
      }
    ?>
    <li>
        <a href ="yourdomainname/<?php echo $page; ?>" <?php echo $class; ?>>
           link<?= $key; ?>
        </a>
    </li>
    <php
    }
    ?>

回答3:

Your idea is ok. Thing is, your keys end with .php and your <li> classes look up abt-shop, no .php, so they don't find anything.

回答4:

I only understood

If I have 20 links, this script would be way too long.... Thank you!

Well, that is when the for loop, comes in handy.

<?php for($i=0; $i<20; $i++){ ?>

<li>
    <a href ="<?php echo $arr['abt-shop']; ?>"
       class="<?php echo "$class.$i" ?>">
       link<?= $i; ?>
    </a>
</li>

<?php } ?>

UPDATE

---

<?php $arr = array( '1' => '/about.php', 
                    '2'=> '/abt-history2.php',
                    '3' => '/abt-shop.php', );


 $host = $_SERVER['REQUEST_URI'];


 switch($host){

 case $arr['1'];
        $class1 = "active";
    break; 
case $arr['2'];
        $class2 = "active";
    break; 
case $arr['3'];
        $class3 = "active";
    break; 
case $arr['4'];
        $class4 = "active";
    break; 



 }

来源：https://stackoverflow.com/questions/15717516/php-condition-if-current-page-then-link-is-highlighted