Bash: how to use sed to replace only the last occurence in a file?

问题

Having a file containing repeated commented lines like:

# ScriptAlias /cgi-bin/ "somepath"
# ScriptAlias /cgi-bin/ "otherpath"

I want to add a line only after the last occurence resulting in

# ScriptAlias /cgi-bin/ "somepath"
# ScriptAlias /cgi-bin/ "otherpath"
ScriptAlias /cgi-bin/ "mypath"

To do so I'm using this command:

sed -i 's:^\(.*ScriptAlias /cgi-bin/.*\):\1 \nScriptAlias /cgi-bin/ "mypath":' file

But this results in adding my line after each occurence like:

# ScriptAlias /cgi-bin/ "somepath"
ScriptAlias /cgi-bin/ "mypath"
# ScriptAlias /cgi-bin/ "otherpath"
ScriptAlias /cgi-bin/ "mypath"

How can I tell sed to replace only the last occurence?

EDITED:
If there's no way to solve it using sed (as said in comments), please provide alternatives reaching the same result, thanks.

EDITED:
The repeated lines can be separeted and with other lines between them like

# ScriptAlias /cgi-bin/ "somepath"
# ScriptAlias /cgi-bin/ "otherpath"

# ScriptAlias /cgi-bin/ "another-path"
ScriptAlias /foo/ "just-jump"
# ScriptAlias /cgi-bin/ "that's the last"

回答1:

Use tac so you print your new line the first time you see the pattern:

tac file | awk '/ScriptAlias/ && ! seen {print "new line"; seen=1} {print}' | tac

回答2:

alternative with awk:

awk '/ScriptAlias \/cgi-bin\//{x=NR} {a[NR]=$0;}END{for(i=1;i<=NR;i++){if(i==x+1)print "$$$here comes new line$$$"; print a[i];}}' file

test:

kent$  echo "# ScriptAlias /cgi-bin/ "somepath"
fooo
# ScriptAlias /cgi-bin/ "otherpath"
bar
"|awk '/ScriptAlias \/cgi-bin\//{x=NR} {a[NR]=$0;}END{for(i=1;i<=NR;i++){if(i==x+1)print "$$$here comes new line$$$"; print a[i];}}'

output:

# ScriptAlias /cgi-bin/ somepath
fooo
# ScriptAlias /cgi-bin/ otherpath
$$$here comes new line$$$
bar

回答3:

tail -r temp | awk '{line="yourline"}{if($0~/ScriptAlias/&&last==0){print line"\n"$0;last=1}else print}' | tail -r

tested below:

krithika.337> cat temp
# ScriptAlias /cgi-bin/ "somepath" 
# ScriptAlias /cgi-bin/ "otherpath" 
# ndmxriptAlias /cgi-bin/ "otherpath" 
# ScriptAlias /cgi-bin/ "otherpath" 
# bdjiptAlias /cgi-bin/ "otherpath" 
krithika.338> tail -r temp | awk '{line="yourline"}{if($0~/ScriptAlias/&&last==0){print line"\n"$0;last=1}else print}' | tail -r
# ScriptAlias /cgi-bin/ "somepath" 
# ScriptAlias /cgi-bin/ "otherpath" 
# ndmxriptAlias /cgi-bin/ "otherpath" 
# ScriptAlias /cgi-bin/ "otherpath" 
yourline
# bdjiptAlias /cgi-bin/ "otherpath" 
krithika.339>

回答4:

It is a task for the editor.

ex input_file << "DONE"
/ScriptAlias \/cgi-bin\/ "otherpath"
a
ScriptAlias /cgi-bin/ "mypath"
.
:1
/ScriptAlias \/cgi-bin\/ "another-path"
a
ScriptAlias /cgi-bin/ "just-jump"
.
:x
DONE

In last occurence mode.

ex input_file << "DONE"
$
?ScriptAlias \/cgi-bin\/ "otherpath"
a
ScriptAlias /cgi-bin/ "mypath"
.
$
?ScriptAlias \/cgi-bin\/ "another-path"
a
ScriptAlias /cgi-bin/ "just-jump"
.
:x
DONE

来源：https://stackoverflow.com/questions/10106292/bash-how-to-use-sed-to-replace-only-the-last-occurence-in-a-file

标签

bash

replace

sed

awk

last-occurrence