Run application both as server and client

问题

I want to make my pc both server and client. This is my code

import java.net.*;
class tester {
static int pos=0; 
 static byte buffer[]=new byte[100];
   static void Client() throws Exception {
    InetAddress address=InetAddress.getLocalHost();
  DatagramSocket ds=new DatagramSocket(3000,address);
   while(true) {
    int c=System.in.read();
    buffer[pos++]=(byte)c;
    if((char)c=='\n')
      break;
   }
   ds.send(new DatagramPacket(buffer,pos,address,3000));
  Server();
}                   

static void Server() throws Exception {
 InetAddress address=InetAddress.getLocalHost();
 DatagramSocket ds=new DatagramSocket(3001,address);
 DatagramPacket dp=new DatagramPacket(buffer,buffer.length);
 ds.receive(dp);
 System.out.print(new String(dp.getData(),0,dp.getLength()));
}
  public static void main(String args[])throws Exception {

 if(args.length==1) {
  Client();
   } 
 }

}

In this I have tried to make my computer both server and client. I run this program on cmd as java tester hello but the program keeps on waiting.What should i do to receive message typed.?

*If there is any amendment to be made in the code please suggest that.Note that the aim is to make my pc both server and client.

回答1:

Currently your application will either run as the server or the client, depending on whether or not you provide a command line argument. To run as both within the same process, you'd want to start two threads (at least) - one for the server and one for the client.

For the moment though, I'd just start it up twice in two different command windows - once with a command line argument (to make it the client) and once without (to make it the server).

EDIT: I've just noticed that your main method will never run Server(). So you need to change it to something like this:

if (args.length == 1) {
  Client();
} else {
  Server();
}

(You might also want to start following Java naming conventions at the same time, by the way, renaming the methods to client() and server().)

Then remove the Server() call from the end of Client(), and call the parameterless DatagramSocket constructor in Client() to avoid trying to be a server...

The finished code might look something like this:

import java.io.IOException;
import java.net.*;

public class ClientServer {

   private static void runClient() throws IOException {
     InetAddress address = InetAddress.getLocalHost();
     DatagramSocket ds=new DatagramSocket();
     int pos = 0;
     byte[] buffer = new byte[100];
     while (pos < buffer.length) {
       int c = System.in.read();
       buffer[pos++]=(byte)c;
       if ((char)c == '\n') {
         break;
       }
     }
     System.out.println("Sending " + pos + " bytes");
     ds.send(new DatagramPacket(buffer, pos, address, 3000));
  }                   

  private static void runServer() throws IOException {
    byte[] buffer = new byte[100];
    InetAddress address = InetAddress.getLocalHost();
    DatagramSocket ds = new DatagramSocket(3000, address);
    DatagramPacket dp = new DatagramPacket(buffer, buffer.length);
    ds.receive(dp);
    System.out.print(new String(dp.getData(), 0, dp.getLength()));
  }

  public static void main(String args[]) throws IOException {
    if (args.length == 1) {
      runClient();
    } else {
      runServer();
    }
  }
}

Note that this still isn't great code, in particular using the system default string encoding... but it works. Start the server in one window by running java ClientServer, then in another window run java ClientServer xxx, type a message and press return. You should see it in the server window.

来源：https://stackoverflow.com/questions/5433378/run-application-both-as-server-and-client