Removing lines from UIImage in ios

问题

I have an image in UIImageView. I have drawn lines on the image sucdcessfully.Now I want to remove that specific line on which user will perform a long press gesture. how can I do that ? my code is :

{

        // gets the location in the form of (x,y) coordinates
        CGPoint  location=[sender locationInView:imageView];
        // convetrs the location relative to the image
        CGPoint contextLocation = CGPointMake(location.x*imageView.image.size.width/imageView.frame.size.width, location.y*imageView.image.size.height/imageView.frame.size.height);
        // converts the location point into NSValue
        NSValue *imagePoint=[NSValue valueWithCGPoint:contextLocation];
        // Adds the  image into NSMutable Array
        [imageLocations addObject:imagePoint];
        // color of line
        UIColor * linearcolor=[UIColor blueColor];


        UIGraphicsBeginImageContext(imageView.image.size);

        [imageView.image drawAtPoint:CGPointMake(0, 0)];


        CGContextRef context=UIGraphicsGetCurrentContext();

        // Brush widt
        CGContextSetLineWidth(context, 3.0);
        // Line Color
        CGContextSetStrokeColorWithColor(context, [linearcolor CGColor]);
        // Hard coded point for location 2
        CGPoint location2=CGPointMake(300, 400);


        CGContextMoveToPoint(context, contextLocation.x, contextLocation.y);

        CGContextAddLineToPoint(context, location2.x, location2.y);
        CGContextStrokePath(context);

        newImage=UIGraphicsGetImageFromCurrentImageContext();

        UIGraphicsEndImageContext();
        imageView.image=newImage;



    }

回答1:

What you need to do is find the line pressed and remove it from the array of points you have and then redraw the whole image with the lines.

I guess the problem is in how to find the correct line:

Lets say you have a location L gotten from the gesture. Then what you need is to iterate through all the point pairs such as

for(NSInteger i=0; i< imageLocations.count.count-1; i+=2)
{
   CGPoint T1 = [imageLocations[i] CGPointValue];
   CGPoint T2 = [imageLocations[i+1] CGPointValue];
}

Now you have points L, T1, T2. From here there are many ways to detect if the line is hit. What I like most is to first use a dot product to see if the press is near the line like so:

CGFloat dotValue = dot(normalized(T1-L), normalized(T2-L))

Find the procedures for the dot product and the normalization of a point online. Now the dotValue should be near -1 for the line to be hit. You should use something like if(dotValue > -.7f) continue; to remove all the lines too far from the press along the line.

Next is to actually find the line distance from the point. This is actually a Z component of a cross product:

CGFloat crossValue = fabsf(cross((L-T1), normalized(T2-T1)).z);

I know you have no Z component so use:

crossValue = A.x*B.y - A.y*B.x

So now that you have all this the pseudo code should be something like this:

CGPoint L;
NSInteger bestLineIndex = -1;
CGFloat bestLineDistance = 10000.0f; // something large

for (CGPoint T1, T2; NSInteger index)
{
    dotValue = ...
    if(dotValue < -.7)
    {
        crossValue = ...
        if(crossValue < bestLineDistance)
        {
           bestLineDistance = crossValue;
           bestLineIndex = index;
        }
    }
}

So in the end you have the index of your first line point which should be removed if not -1 (if -1 no line was found near the touch).

For line distance from a point using a cross product:

- (CGFloat)distanceBetweenPoint:(CGPoint)L andLineWithStart:(CGPoint)T1 end:(CGPoint)T2
{
    CGPoint T1toL = CGPointMake(L.x-T1.x, L.y-T1.y);
    CGPoint T2toL = CGPointMake(L.x-T2.x, L.y-T2.y);

    CGFloat T2toLDistance = sqrt(T2toL.x*T2toL.x + T2toL.y*T2toL.y);
    CGPoint T2toLNormalized = CGPointMake(T2toL.x/T2toLDistance, T2toL.y/T2toLDistance);

    CGFloat zComponentOfCross = T1toL.x*T2toLNormalized.y - T1toL.y*T2toLNormalized.x;

    return fabs(zComponentOfCross);
}

回答2:

It's simple. I add my code below as your question.

// gets the location in the form of (x,y) coordinates
    CGPoint  location=[sender locationInView:imageView];
    // convetrs the location relative to the image
    CGPoint contextLocation = CGPointMake(location.x*imageView.image.size.width/imageView.frame.size.width, location.y*imageView.image.size.height/imageView.frame.size.height);
    // converts the location point into NSValue
    NSValue *imagePoint=[NSValue valueWithCGPoint:contextLocation];
    // Adds the  image into NSMutable Array
    [imageLocations addObject:imagePoint];
    // color of line
    UIColor * linearcolor=[UIColor blueColor];


    UIGraphicsBeginImageContext(imageView.image.size);

    [imageView.image drawAtPoint:CGPointMake(0, 0)];


    CGContextRef context=UIGraphicsGetCurrentContext();

    // Brush widt
    CGContextSetLineWidth(context, 3.0);

    **CGContextSetBlendMode(UIGraphicsGetCurrentContext(), kCGBlendModeClear);**

    // Hard coded point for location 2
    CGPoint location2=CGPointMake(300, 400);


    CGContextMoveToPoint(context, contextLocation.x, contextLocation.y);

    CGContextAddLineToPoint(context, location2.x, location2.y);
    CGContextStrokePath(context);

    newImage=UIGraphicsGetImageFromCurrentImageContext();

    UIGraphicsEndImageContext();
    imageView.image=newImage;
}

Hope this is helpful.Enjoy.

来源：https://stackoverflow.com/questions/27983655/removing-lines-from-uiimage-in-ios

标签

ios

uiimageview

uiimage