问题
Is there a way to programmatically find the path of an R script inside the script itself?
I am asking this because I have several scripts that use RGtk2 and load a GUI from a .glade file.
In these scripts I am obliged to put a setwd("path/to/the/script") instruction at the beginning, otherwise the .glade file (which is in the same directory) will not be found.
This is fine, but if I move the script in a different directory or to another computer I have to change the path. I know, it's not a big deal, but it would be nice to have something like:
setwd(getScriptPath())
So, does a similar function exist?
回答1:
Use source("yourfile.R", chdir = T)
回答2:
This works for me:
getSrcDirectory(function(x) {x})
This defines an anonymous function (that does nothing) inside the script, and then determines the source directory of that function, which is the directory where the script is.
回答3:
For RStudio only:
setwd(dirname(rstudioapi::getActiveDocumentContext()$path))
This works when Running or Sourceing your file.
回答4:
Exploit the implicit "--file" argument of Rscript
When calling the script using "Rscript" (Rscript doc) the full path of the script is given as a system parameter. The following function exploits this to extract the script directory:
getScriptPath <- function(){
cmd.args <- commandArgs()
m <- regexpr("(?<=^--file=).+", cmd.args, perl=TRUE)
script.dir <- dirname(regmatches(cmd.args, m))
if(length(script.dir) == 0) stop("can't determine script dir: please call the script with Rscript")
if(length(script.dir) > 1) stop("can't determine script dir: more than one '--file' argument detected")
return(script.dir)
}
回答5:
If you wrap your code in a package, you can always query parts of the package directory.
Here is an example from the RGtk2 package:
> system.file("ui", "demo.ui", package="RGtk2")
[1] "C:/opt/R/library/RGtk2/ui/demo.ui"
>
You can do the same with a directory inst/glade/ in your sources which will become a directory glade/ in the installed package -- and system.file() will compute the path for you when installed, irrespective of the OS.
回答6:
This answer works fine to me:
script.dir <- dirname(sys.frame(1)$ofile)
Note: script must be sourced in order to return correct path
I found it in: https://support.rstudio.com/hc/communities/public/questions/200895567-can-user-obtain-the-path-of-current-Project-s-directory-
But I still don´t understand what is sys.frame(1)$ofile. I didn´t find anything about that in R Documentation. Someone can explain it?
回答7:
#' current script dir
#' @param
#' @return
#' @examples
#' works with source() or in RStudio Run selection
#' @export
z.csd <- function() {
# http://stackoverflow.com/questions/1815606/rscript-determine-path-of-the-executing-script
# must work with source()
if (!is.null(res <- .thisfile_source())) res
else if (!is.null(res <- .thisfile_rscript())) dirname(res)
# http://stackoverflow.com/a/35842176/2292993
# RStudio only, can work without source()
else dirname(rstudioapi::getActiveDocumentContext()$path)
}
# Helper functions
.thisfile_source <- function() {
for (i in -(1:sys.nframe())) {
if (identical(sys.function(i), base::source))
return (normalizePath(sys.frame(i)$ofile))
}
NULL
}
.thisfile_rscript <- function() {
cmdArgs <- commandArgs(trailingOnly = FALSE)
cmdArgsTrailing <- commandArgs(trailingOnly = TRUE)
cmdArgs <- cmdArgs[seq.int(from=1, length.out=length(cmdArgs) - length(cmdArgsTrailing))]
res <- gsub("^(?:--file=(.*)|.*)$", "\\1", cmdArgs)
# If multiple --file arguments are given, R uses the last one
res <- tail(res[res != ""], 1)
if (length(res) > 0)
return (res)
NULL
}
回答8:
A lot of these solutions are several years old. While some may still work, there are good reasons against utilizing each of them (see linked source below). I have the best solution (also from source): use the here library.
Original example code:
library(ggplot2)
setwd("/Users/jenny/cuddly_broccoli/verbose_funicular/foofy/data")
df <- read.delim("raw_foofy_data.csv")
Revised code
library(ggplot2)
library(here)
df <- read.delim(here("data", "raw_foofy_data.csv"))
This solution is the most dynamic and robust because it works regardless of whether you are using the command line, RStudio, calling from an R script, etc. It is also extremely simple to use and is succinct.
Source: https://www.tidyverse.org/articles/2017/12/workflow-vs-script/
回答9:
How about using system and shell commands? With the windows one, I think when you open the script in RStudio it sets the current shell directory to the directory of the script. You might have to add cd C:\ e.g or whatever drive you want to search (e.g. shell('dir C:\\*file_name /s', intern = TRUE) - \\ to escape escape character). Will only work for uniquely named files unless you further specify subdirectories (for Linux I started searching from /). In any case, if you know how to find something in the shell, this provides a layout to find it within R and return the directory. Should work whether you are sourcing or running the script but I haven't fully explored the potential bugs.
#Get operating system
OS<-Sys.info()
win<-length(grep("Windows",OS))
lin<-length(grep("Linux",OS))
#Find path of data directory
#Linux Bash Commands
if(lin==1){
file_path<-system("find / -name 'file_name'", intern = TRUE)
data_directory<-gsub('/file_name',"",file_path)
}
#Windows Command Prompt Commands
if(win==1){
file_path<-shell('dir file_name /s', intern = TRUE)
file_path<-file_path[4]
file_path<-gsub(" Directory of ","",file_path)
filepath<-gsub("\\\\","/",file_path)
data_directory<-file_path
}
#Change working directory to location of data and sources
setwd(data_directory)
回答10:
Thank you for the function, though I had to adjust it a Little as following for me (W10):
#Windows Command Prompt Commands
if(win==1){
file_path<-shell('dir file_name', intern = TRUE)
file_path<-file_path[4]
file_path<-gsub(" Verzeichnis von ","",file_path)
file_path<-chartr("\\","/",file_path)
data_directory<-file_path
}
来源：https://stackoverflow.com/questions/35112128/how-do-i-get-script-directory-in-r