Why is my c != 'o' || c != 'x' condition always true? [duplicate]

|▌冷眼眸甩不掉的悲伤 提交于 2019-11-26 01:50:39

问题


I have this loop statement, which I\'ll express using C-like syntax (C, C++, Java, JavaScript, PHP, etc. all use similar syntax):

while (c != \'o\' || c != \'x\') {
    c = getANewValue();
}

I want it to run until I get a \'o\' or \'x\', but it never exits, even when c is \'o\' or \'x\'. Why not?

I\'ve also tried using if:

if (c != \'o\' || c != \'x\') {
    // Show an error saying it must be either \'o\' or \'x\'
}

but that also always shows the error message, even when c is \'o\' or \'x\'. Why?


回答1:


It must be if(c!='o' && c!='x') instead of if(c!='o' || c!='x'). If you use the or operator the boolean expression will be always true.




回答2:


The condition (c != 'o' || c != 'x') can never be false. If c is 'o', then c != 'x' will be true and the OR condition is satisfied. If c is 'x', then c != 'o' will be true and the OR condition is satisfied.

You want && (AND), not || (OR):

while (c != 'o' && c != 'x') {
    // ...
}

"While c is NOT 'o' AND c is NOT `'x'..." (e.g., it's neither of them).

Or use De Morgan's law, covered here:

while (!(c == 'o' || c == 'x')) {
    // ...
}

"While it's NOT true that (c is 'o' or c is 'x')..."




回答3:


Why is my c != 'o' || c != 'x' condition always true?

The expression combines two sub-expressions using the logical OR operator (||). The expression is true if at least one of the sub-expressions is true. In order to be false, both sub-expressions it connects must be false.

The sub-expressions are c != 'o' and c != 'x'.

The first sub-expression c != 'o' is false when c == 'o'. The same for the second one; it is false when c == 'x'.

Please note that they cannot be false on the same time because c cannot be 'o' and 'x' on the same time.




回答4:


The condition should be if(!(c=='o' || c=='x')) or if(c!='o' && c!='x')




回答5:


even when you enter x or you enter o in that case if condition evaluates to true and hence game_start remains false.

it should be if(c!='o' && c!='x') or use a more straight forward way

if(c == 'o' || c == 'x')
   game_start=true;
else
    System.out.println("you can only enter o or x!");


来源:https://stackoverflow.com/questions/36605454/why-is-my-c-o-c-x-condition-always-true

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!