how to dynamically update a plot in a loop in ipython notebook (within one cell)

|▌冷眼眸甩不掉的悲伤 提交于 2019-11-27 02:38:02
HYRY

use IPython.display module:

%matplotlib inline
import time
import pylab as pl
from IPython import display
for i in range(10):
    pl.plot(pl.randn(100))
    display.clear_output(wait=True)
    display.display(pl.gcf())
    time.sleep(1.0)

You can further improve this by adding wait=True to clear_output:

display.clear_output(wait=True)
display.display(pl.gcf())
Tom Phillips

A couple of improvement's on HYRY's answer:

  • call display before clear_output so that you end up with one plot, rather than two, when the cell is interrupted.
  • catch the KeyboardInterrupt, so that the cell output isn't littered with the traceback.
import matplotlib.pylab as plt
import pandas as pd
import numpy as np
import time
from IPython import display
%matplotlib inline

i = pd.date_range('2013-1-1',periods=100,freq='s')

while True:
    try:
        plt.plot(pd.Series(data=np.random.randn(100), index=i))
        display.display(plt.gcf())
        display.clear_output(wait=True)
        time.sleep(1)
    except KeyboardInterrupt:
        break

Try to add show() or gcf().show() after the plot() function. These will force the current figure to update (gcf() returns a reference for the current figure).

Adding label to the other solutions posted here will keep adding new labels in every loop. To deal with that, clear the plot using clf

for t in range(100)
   if t % refresh_rate == 0:

     plt.clf()
     plt.plot(history['val_loss'], 'r-', lw=2, label='val')
     plt.plot(history['training_loss'], 'b-', lw=1, label='training')
     plt.legend()
     display.clear_output(wait=True)
     display.display(plt.gcf())

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