问题
Although I searched about it I couldn't find an answer.
Let's say I have the following Java code:
ServerSocket serve = null;
try {
server = new ServerSocket(5567);
} catch (IOException e) {
System.err.println("Problem with port 5567");
System.exit(1);
}
Socket clientSocket = null;
try {
clientSocket = server.accept();
} catch (IOException e) {
System.exit(1);
}
When server.accept()
is being called the program blocks until someone connects to my server. Is there a way, to be able to find the IP of the program/user who connects to my server?
回答1:
Try
Socket clientSocket = null;
try {
clientSocket = server.accept();
System.out.println("Connected from " + clientSocket .getInetAddress() + " on port "
+ clientSocket .getPort() + " to port " + clientSocket .getLocalPort() + " of "
+ clientSocket .getLocalAddress());
} catch (IOException e) {
System.exit(1);
}
来源:https://stackoverflow.com/questions/4999408/find-ip-of-program-trying-to-connect-to-serversocket