Checking for a range in Powershell

Question

I'm trying to write a script that will get an IP address of a computer and check to see whether it falls in a specific range of IPs. So for example, if the IP of the machine is 192.168.0.5, the script will check to see if it falls between the range 192.168.0.10 to 192.168.0.20. So far, my script is only able to get IPs of remote machines, but I just can't figure out how I would check if the IP is in a specific range. I'd appreciate any suggestions. Thank you.

Answer 1

It might be easiest to let .NET do the work - there's an IPAddress class that can parse them to their numeric values for comparison. Here's a function that you can drop into your profile (or add to a module, or however you prefer to add PS functions):

function IsIpAddressInRange {
param(
        [string] $ipAddress,
        [string] $fromAddress,
        [string] $toAddress
    )

    $ip = [system.net.ipaddress]::Parse($ipAddress).GetAddressBytes()
    [array]::Reverse($ip)
    $ip = [system.BitConverter]::ToUInt32($ip, 0)

    $from = [system.net.ipaddress]::Parse($fromAddress).GetAddressBytes()
    [array]::Reverse($from)
    $from = [system.BitConverter]::ToUInt32($from, 0)

    $to = [system.net.ipaddress]::Parse($toAddress).GetAddressBytes()
    [array]::Reverse($to)
    $to = [system.BitConverter]::ToUInt32($to, 0)

    $from -le $ip -and $ip -le $to
}

Usage looks like:

PS> IsIpAddressInRange "192.168.0.5" "192.168.0.10" "192.168.0.20"
False
PS> IsIpAddressInRange "192.168.0.15" "192.168.0.10" "192.168.0.20"
True

Answer 2

This is a simple task for the -Like operator in PowerShell:

For example:

$ipaddress -like "192.168.1.*"

Answer 3

Came across this one when googling, rather high hit. Just wanted to say that at least in powershell 4 and 5 it's a lot easier:

$range = "10.10.140.0-10.11.15.0"
$ipStart,$ipEnd = $range.Split("-")

$ipCheck = "10.10.250.255"

($ipCheck -ge $ipStart) -AND ($ipCheck -le $ipEnd)

---

This is not working, if you give an IP 192.168.25.75 within range 192.168.25.0-192.168.25.255.

Answer 4

i write a little function to do this:

function Test-IpAddressInRange {
    [CmdletBinding()]
    param (
        [Parameter(Position = 0, Mandatory = $true)][ipaddress]$from,
        [Parameter(Position = 1, Mandatory = $true)][ipaddress]$to,
        [Parameter(Position = 2, Mandatory = $true)][ipaddress]$target
    )
    $f=$from.GetAddressBytes()|%{"{0:000}" -f $_}   | & {$ofs='-';"$input"}
    $t=$to.GetAddressBytes()|%{"{0:000}" -f $_}   | & {$ofs='-';"$input"}
    $tg=$target.GetAddressBytes()|%{"{0:000}" -f $_}   | & {$ofs='-';"$input"}
    return ($f -le $tg) -and ($t -ge $tg)
}

test result:

PS C:\> Test-IpAddressInRange "192.168.0.1"  "192.168.0.100"  "192.168.0.1"
True
PS C:\> Test-IpAddressInRange "192.168.0.1"  "192.168.0.100"  "192.168.0.100"
True
PS C:\> Test-IpAddressInRange "192.168.90.1"  "192.168.100.100"  "192.168.101.101"
False
PS C:\>

Answer 5

It's easy if mask is 255.255.255.0 in this case you can do something like this:

$a = [ipaddress]"192.168.0.5"

10..20 -contains $a.IPAddressToString.split('.')[3]

true

For different submask you have to check each ip's octect.

Answer 6

For seeing if an IP is in range 192.168.1.10 to 192.168.1.20, for example, you can use regex and the -match operator

 $ip -match "192\.168\.1\.0?(1\d)|20"

The 0? is to allow a leading 0.

Similarly, for any range, you can use a regex.

For very simple range, use string split on . and operate on the components.