问题
When I try to run this
int N=10000000;
short res[N];
I get segmentation fault 11
when I change to
int N=1000000;
short res[N];
it works fine
回答1:
You've exceeded your stack space given by the OS. If you need more memory, the easiest way is to allocate it dynamically:
int N=1000000;
short* res = new short[N];
However, std::vector is preferred in this context, because the above requires you to free the memory by hand.
int N = 1000000;
std::vector<short> res (N);
If you can use C++11, you can possibly save some fraction of time by using unique_ptr array specialization, too:
std::unique_ptr<short[]> res (new short[N]);
Both of the automatic methods above can still be used with familiar res[index] syntax thanks to overloaded operator[], but to get the raw pointer for memory operations you'd need res.data() with vector or res.get() with unique_ptr.
回答2:
You can't allocate all that on the stack. Try short* res = new short[10000000]; and don't forget to clean up.
Alternatively, you can use std::vector<short> res(10000000);
来源：https://stackoverflow.com/questions/19522192/segmentation-fault-11-in-c-on-mac