问题
What do double square brackets mean in a regex? I am confused about the following examples:
/[[^abc]]/
/[^abc]/
I was testing using Rubular, but I didn't see any difference between the one with double brackets and single brackets.
回答1:
Posix character classes use a [:alpha:] notation, which are used inside a regular expression like:
/[[:alpha:][:digit:]]/
You'll need to scroll down a ways to get to the Posix information in the link above. From the docs:
POSIX bracket expressions are also similar to character classes. They provide a portable alternative to the above, with the added benefit that they encompass non-ASCII characters. For instance, /\d/ matches only the ASCII decimal digits (0-9); whereas /[[:digit:]]/ matches any character in the Unicode Nd category.
/[[:alnum:]]/ - Alphabetic and numeric character
/[[:alpha:]]/ - Alphabetic character
/[[:blank:]]/ - Space or tab
/[[:cntrl:]]/ - Control character
/[[:digit:]]/ - Digit
/[[:graph:]]/ - Non-blank character (excludes spaces, control characters, and similar)
/[[:lower:]]/ - Lowercase alphabetical character
/[[:print:]]/ - Like [:graph:], but includes the space character
/[[:punct:]]/ - Punctuation character
/[[:space:]]/ - Whitespace character ([:blank:], newline,
carriage return, etc.)
/[[:upper:]]/ - Uppercase alphabetical
/[[:xdigit:]]/ - Digit allowed in a hexadecimal number (i.e., 0-9a-fA-F)
Ruby also supports the following non-POSIX character classes:
/[[:word:]]/ - A character in one of the following Unicode general categories Letter, Mark, Number, Connector_Punctuation
/[[:ascii:]]/ - A character in the ASCII character set
# U+06F2 is "EXTENDED ARABIC-INDIC DIGIT TWO"
/[[:digit:]]/.match("\u06F2") #=> #<MatchData "\u{06F2}">
/[[:upper:]][[:lower:]]/.match("Hello") #=> #<MatchData "He">
/[[:xdigit:]][[:xdigit:]]/.match("A6") #=> #<MatchData "A6">
回答2:
'[[' doesn't have any special meaning. [xyz] is a character class and will match a single x, y or z. The carat ^ takes all characters not in the brackets.
Removing ^ for simplicity, you can see that the first open bracket is being matched with the first close bracket and the second closed bracket is being used as part of the character class. The final close bracket is treated as another character to be matched.
irb(main):032:0> /[[abc]]/ =~ "[a]"
=> 1
irb(main):033:0> /[[abc]]/ =~ "a]"
=> 0
This appears to have the same result as your original in some cases
irb(main):034:0> /[abc]/ =~ "a]"
=> 0
irb(main):034:0> /[abc]/ =~ "a"
=> 0
But this is only because your regular expression is not looking for an exact match.
irb(main):036:0> /^[abc]$/ =~ "a]"
=> nil
来源：https://stackoverflow.com/questions/12275332/how-to-use-double-brackets-in-a-regular-expression