brackets

How to extract commas in between square brackets in notepad++?

由 隐身守侯 提交于 2021-02-17 03:39:11
问题 For example: [TEXT1,TEXT2,TEXT3] my expression: [\[].*,.*[\]] Finds strings with commas (in between brackets,) but I only want to explicitly match the comma that exists in the square brackets. I need to replace the commas with spaces - but only in the square brackets. I've tried [\[],[\]] but that doesn't work - \[(.*?)\] will find the text in between as well - but I do not want the entire string. Can anyone suggest what I need to do to just find commas in between the brackets? 回答1: Find what

10个 IDEA 插件，帮你解放双手的

由 痴心易碎 提交于 2021-02-15 23:30:16
❝ 友情提示：插件虽好，可不要贪装哦，装多了会 卡 、卡 、卡 ~ ❞ 正经干活用的 分享一点自己工作中得心应手的 IDEA 插件，都经过实战检验，超好用哦~ 集成插件后会再去使用 Executors 去创建线程池会有如下的提示。 在这里插入图片描述 在这里插入图片描述 Conflicts(冲突) All Dependencies as List(列表形式查看所有依赖) All Dependencies as Tree(树结构查看所有依赖)，并且这个页面还支持搜索。 在这里插入图片描述 IDEA 还有不少的开发小技巧，有助于我们少些代码，不知道大家有没有发现？变量后 . 可以联想提示，而在联想列表的最后边有很多简洁的命令。 装X用的 下边这些就属于装X神器了，可以根据个人的喜好来耍一下。 4、Rainbow Brackets 彩虹颜色的括号，看着很舒服，有点赏心悦目的感觉。 本文分享自微信公众号 - V5codings（gh_c1ec2d16ec93）。 如有侵权，请联系 support@oschina.cn 删除。 本文参与“ OSC源创计划 ”，欢迎正在阅读的你也加入，一起分享。 来源： oschina 链接： https://my.oschina.net/u/4599382/blog/4470275

12.Git分支-推送（push）、跟踪分支、拉取（pull）、删除远程分支

由 生来就可爱ヽ(ⅴ＜●) 提交于 2021-02-14 10:21:56
1.推送 　　本地的分支并不会自动与远程仓库同步，你可以显示的向远程仓库推送你的分支。例如你在本地创建了一个dev分支，你想其他的人和你一样在dev之下进行工作，可以使用 git push <remote> <branch> 将自己的分支推送到远程仓库。 　　 git push origin dev 即可。 　　 下一次其他的人从服务器上抓取数据的时候，他们会在本地生成一个远程分支origin/serverfix，指向服务器的serverfix分支的引用。 　　如果你在推送分支的时候，想给分支另取一个名字，可以使用 git push <remote> <branch>:<remote-branch> 　　例如 git push <origin> <dev>:<dev-gq> ，将本地的dev分支推送到远程，并且远程分支命名为dev-gq。 注意： 当使用git fetch从远程仓库抓取到新的远程跟踪分支时，本地不会自动生成一份可编辑的副本。换句话说，也就是本地不会自动生成一个新的dev分支，只有一个不可以进行修改的origin/dev分支。 　　你可以运行 git merge <origin/dev> 将这些跟踪合并到你正在工作的分支上。当然你也可以在远程跟踪分支上新建一个dev分支， git checkout -b dev origin/dev

Why an IF block is allowed inside another IF that doesn't have curly brackets in JAVA [duplicate]

由 妖精的绣舞 提交于 2021-02-05 06:54:44
问题 This question already has answers here : Is there a difference in removing the curly braces from If statements in java (17 answers) Closed 7 years ago . Normally in JAVA if an IF statement doesn't have curly brackets can have only one line that is executed when IF condition is met, however if another IF block (inner IF) follows the initial IF, then no error is triggered and there are more lines. How is this possible? Example if (true) if (true) System.out.println("true"); else System.out

Regex to match strings inside brackets with no spaces around

由 给你一囗甜甜゛ 提交于 2021-01-28 05:07:26
问题 I'm using the following regex to match strings inside brackets: \((.*?)\) But this matches this: (word) and this too: ( word ) I need to modify it to only match the first case: words inside brackets with no spaces around: (word) Any ideas? Thanks in advance 回答1: Use lookahead/lookbehind to disallow space after the opening parenthesis and before the closing parenthesis: \((?!\s)[^()]+(?<!\s)\) (?!\s) and (?<!\s) mean "not followed by / not preceded by a space". The part in the middle, [^()]+

valid bracket list in prolog

由 会有一股神秘感。 提交于 2021-01-27 04:10:36
问题 I'm trying to test if a list of brackets is valid. My code: checkbrackets([]). checkbrackets(['('|T]):- T = [')'|List], checkbrackets(List). checkbrackets(['('|T]):- T = ['('|List], append(Rest,[')'],T), checkbrackets(Rest). My code works for ['(', '(', ')', '(', '(', ')', ')', ')'] but it fails for ['(', '(', ')', ')', '(', ')'] . What am I doing wrong? Is it possible to write such a test without additional arguments like counters? 回答1: For the sake of completeness, here is a solution

valid bracket list in prolog

由 痞子三分冷 提交于 2021-01-27 04:10:36
问题 I'm trying to test if a list of brackets is valid. My code: checkbrackets([]). checkbrackets(['('|T]):- T = [')'|List], checkbrackets(List). checkbrackets(['('|T]):- T = ['('|List], append(Rest,[')'],T), checkbrackets(Rest). My code works for ['(', '(', ')', '(', '(', ')', ')', ')'] but it fails for ['(', '(', ')', ')', '(', ')'] . What am I doing wrong? Is it possible to write such a test without additional arguments like counters? 回答1: For the sake of completeness, here is a solution

valid bracket list in prolog

由 元气小坏坏 提交于 2021-01-27 04:06:51
问题 I'm trying to test if a list of brackets is valid. My code: checkbrackets([]). checkbrackets(['('|T]):- T = [')'|List], checkbrackets(List). checkbrackets(['('|T]):- T = ['('|List], append(Rest,[')'],T), checkbrackets(Rest). My code works for ['(', '(', ')', '(', '(', ')', ')', ')'] but it fails for ['(', '(', ')', ')', '(', ')'] . What am I doing wrong? Is it possible to write such a test without additional arguments like counters? 回答1: For the sake of completeness, here is a solution

valid bracket list in prolog

由 孤街浪徒 提交于 2021-01-27 04:06:14
问题 I'm trying to test if a list of brackets is valid. My code: checkbrackets([]). checkbrackets(['('|T]):- T = [')'|List], checkbrackets(List). checkbrackets(['('|T]):- T = ['('|List], append(Rest,[')'],T), checkbrackets(Rest). My code works for ['(', '(', ')', '(', '(', ')', ')', ')'] but it fails for ['(', '(', ')', ')', '(', ')'] . What am I doing wrong? Is it possible to write such a test without additional arguments like counters? 回答1: For the sake of completeness, here is a solution

maxima tex output to show brackets for sin and cos

由 久未见 提交于 2021-01-24 09:01:05
问题 I use maxima's tex output and would like to change the way it outputs sin(x). It currently does: tex(sin(x)); $$\sin x$$ But I would like to have brackets around the x, but not always; for instance, if i use this: sin(x/2) already has \left( and \right) tex(sin(x/2)); \begin{equation} \sin \left({{x}\over{2}}\right) \end{equation} is this possible, maybe with the texput function? 回答1: Well, if you are not adverse to putting in a little Lisp code: (%i1) :lisp (setf (get '%sin 'tex) nil) (%i1)
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