zip

How add a file to an existing zip file using Golang

前提是你 提交于 2020-05-29 03:03:19
问题 We can create a zip new file and add files using Go Language. But, how to add a new file with existing zip file using GoLang? If we can use Create function, how to get the zip.writer reference? Bit confused. 回答1: After more analysis, i found that, it is not possible to add any files with the existing zip file. But, I was able to add files with tar file by following the hack given in this URL. 回答2: Although I have not attempted this yet with a zip file that already exists and then writing to

How add a file to an existing zip file using Golang

早过忘川 提交于 2020-05-29 03:03:07
问题 We can create a zip new file and add files using Go Language. But, how to add a new file with existing zip file using GoLang? If we can use Create function, how to get the zip.writer reference? Bit confused. 回答1: After more analysis, i found that, it is not possible to add any files with the existing zip file. But, I was able to add files with tar file by following the hack given in this URL. 回答2: Although I have not attempted this yet with a zip file that already exists and then writing to

Deflating data from MSZIP format

*爱你&永不变心* 提交于 2020-05-28 03:08:06
问题 I'm trying to read a compressed binary .x mesh file but my decompression is failing. The file is basically some directx header info and then a bunch of data in MSZIP format (i.e. 2 bytes are an int blockSize , 2 bytes are a "magic number" and then there are blockSize deflated bytes and then repeat until there's no more data) so for each block I'm just getting the compressed bytes and deflating like so- internal static byte[] DecompressBlock(byte[] data) { var result = new List<byte>(); var ms

Deflating data from MSZIP format

[亡魂溺海] 提交于 2020-05-28 03:07:06
问题 I'm trying to read a compressed binary .x mesh file but my decompression is failing. The file is basically some directx header info and then a bunch of data in MSZIP format (i.e. 2 bytes are an int blockSize , 2 bytes are a "magic number" and then there are blockSize deflated bytes and then repeat until there's no more data) so for each block I'm just getting the compressed bytes and deflating like so- internal static byte[] DecompressBlock(byte[] data) { var result = new List<byte>(); var ms

Deflating data from MSZIP format

喜夏-厌秋 提交于 2020-05-28 03:05:28
问题 I'm trying to read a compressed binary .x mesh file but my decompression is failing. The file is basically some directx header info and then a bunch of data in MSZIP format (i.e. 2 bytes are an int blockSize , 2 bytes are a "magic number" and then there are blockSize deflated bytes and then repeat until there's no more data) so for each block I'm just getting the compressed bytes and deflating like so- internal static byte[] DecompressBlock(byte[] data) { var result = new List<byte>(); var ms

Can you pre-compress data files to be inserted into a zip file at a later time to improve performance?

故事扮演 提交于 2020-05-26 12:11:46
问题 As part of our installer build, we have to zip thousands of large data files into about ten or twenty 'packages' with a few hundred (or even thousands of) files in each which are all dependent on being kept with the other files in the package. (They are versioned together if you will.) Then during the actual install, the user selects which packages they want included on their system. This also lets them download updates to the packages from our site as one large, versioned file rather than

How to detect a zip-bomb with Java 10

痞子三分冷 提交于 2020-05-25 17:12:10
问题 Apache POI is opening zip-files on a regular basis because Microsoft Excel/Word/... files are zip-files in their newer format. In order to prevent some types of denial-of-service-attacks, it has functionality when opening Zip-files to not read files which expand a lot and thus could be used to overwhelm the main memory by providing a small malicious file which explodes when uncompressed into memory. Apache POI calls this zip-bomb-protection. Up to Java 9 it could use some workaround via

Android ZipInputStream: only DEFLATED entries can have EXT descriptor

北城余情 提交于 2020-05-16 02:26:23
问题 On my android device, I need to extract a file (an xapk, that is a plain zip archive as far as I know) that I get from a content uri. I'm creating the ZipInputStream using this line of code: ZipInputStream zis = new ZipInputStream(getContentResolver().openInputStream(zipUri)); And then I try to read the first entry of the archive with: ZipEntry entry = zis.getNextEntry() The problem is that I get this exception: java.util.zip.ZipException: only DEFLATED entries can have EXT descriptor I'm 100

Android ZipInputStream: only DEFLATED entries can have EXT descriptor

徘徊边缘 提交于 2020-05-16 02:26:09
问题 On my android device, I need to extract a file (an xapk, that is a plain zip archive as far as I know) that I get from a content uri. I'm creating the ZipInputStream using this line of code: ZipInputStream zis = new ZipInputStream(getContentResolver().openInputStream(zipUri)); And then I try to read the first entry of the archive with: ZipEntry entry = zis.getNextEntry() The problem is that I get this exception: java.util.zip.ZipException: only DEFLATED entries can have EXT descriptor I'm 100

what is meaning of [iter(list)]*2 in python?

本小妞迷上赌 提交于 2020-05-15 09:26:31
问题 I have found below code in web, result is tuple of two elements in list, how to understand [iter(list)]*2 ? lst = [1,2,3,4,5,6,7,8] b=zip(*[iter(lst)]*2) list(b) [(1, 2), (3, 4), (5, 6), (7, 8)] ------------ [iter(lst)]*2 [<list_iterator at 0x1aff33917f0>, <list_iterator at 0x1aff33917f0>] I check [iter(lst)]*2 , same iterator above, so meaning iter repeat double, so, if i check num from 2 to 3, result should be [(1, 2, 3), (4, 5, 6),(7,8,NaN)] but delete 7,8 lst = [1,2,3,4,5,6,7,8] b=zip(*