xslt-grouping

问题 If I run the following XSLT code: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="text"/> <xsl:key name="kValueByVal" match="variable_name/@value" use="."/> <xsl:template match="assessment"> <xsl:for-each select=" /*/*/variable/attributes/variable_name/@value [generate-id() = generate-id(key('kValueByVal', .)[1]) ] "> <xsl:value-of select= "concat(., ' ', count(key('kValueByVal', .)), ' ')"/> </xsl:for-each> </xsl:template> </xsl:stylesheet>

问题 XSLT 2. Hi, I have an xml that has 3 nodes, named from point of view of the 'children' called: Children, Fathers and MothersFathers. Starting with the Fathers node I need to find the a childs MothersFather node based on the ID's in the Child nodes (the Child node is the intermediate reference joining the other two.) So, for each Father get his children's distinct MothersFather - these aren't humans, a father could have hundreds of children but only twenty or so of the related MothersFathers :

问题 I am looking for a clean way to do the following using XSLT. Convert this source: <para>blah blah</para> <list>num1</list> <list>num2</list> <list>num3</list> <para>blah blah</para> <list>num1</list> <list>num2</list> <para>blah blah blah blah blah</para> To this output: <p>blah blah</p> <ol> <li>num1</li> <li>num2</li> <li>num3</li> </ol> <p>blah blah</p> <ol> <li>num1</li> <li>num2</li> </ol> <p>blah blah blah blah blah</p> Keep in mind I do not know exactly how many <list> 's there will be

问题 With the following file as input of xsltprocessor : mylibrary.xml : <library> <book isbn="1"/> <book isbn="3"/> <book isbn="5"/> </library> and this one that can be used : bookreference.xml : <reference> <book isbn="1"> <category>SF</category> </book> <book isbn="2"> <category>SF</category> </book> <book isbn="3"> <category>SF</category> </book> <book isbn="4"> <category>Comedy</category> </book> <book isbn="5"> <category>Comedy</category> </book> </reference> i want to get the numbers of

问题 I have some xml with thousands of movie elements which can all have 1 or MORE director and writer elements, if a director or writer has the same name as another, as seen here, I add an @differentiator of birthyear, if they are NOT the same person <mediaList> <movie id="1603934" dateCreated="2014-08-11"> <title>Night at the Museum</title> <director>Shawn Levy</director> <LCSpecialTopics>Comedy</LCSpecialTopics> <writer>Robert Ben Garant</writer> <writer differentiator="1970">Thomas Lennon<

问题 I am new to XSLT and need to sum the total price (Quantity * UnitPrice) of items based on ID from each orders, and print it at the end of each Item's group using XSLT 1.0. Here is my example XML <Orders> <Order> <Reference>234</Reference> <Item> <ID>10</ID> <Quantity>1</Quantity> <UnitPrice>2</UnitPrice> </Item> <Item> <ID>10</ID> <Quantity>2</Quantity> <UnitPrice>3</UnitPrice> </Item> <Item> <ID>10</ID> <Quantity>2</Quantity> <UnitPrice>2</UnitPrice> </Item> <Item> <ID>20</ID> <Quantity>2<

问题 I need to apply XSLT 1.0 transformation to following XML: <ProfitLossFinancials> <ProfitLossFinancial> <Year>2013</Year> <Turnover>13</Turnover> <Profit>13</Profit> </ProfitLossFinancial> <ProfitLossFinancial> <Year>2012</Year> <Turnover>12</Turnover> <Profit>12</Profit> </ProfitLossFinancial> </ProfitLossFinancials> <BalanceSheetFinancials> <BalanceSheetFinancial> <Year>2013</Year> <FixedAssets>13</FixedAssets> </BalanceSheetFinancial> <BalanceSheetFinancial> <Year>2011</Year> <FixedAssets

问题 I have to convert the below XML using the XSLT. Input XML is <document> <item> <ID>1000909090</ID> <flex> <attrGroupMany name="pageinfo"> <row> <attrQualMany name="pageinput"> <value qual="en">User Intake</value> </attrQualMany> <attrGroupMany name="pagetype"> <row> <attr name="pagemeasure">EXACT</attr> <attrQualMany name="pagecontain"> <value qual="GR1">20</value> <value qual="GR2">21</value> </attrQualMany> </row> <row> <attr name="pagemeasure">EXACT</attr> <attrQualMany name="pagecontain">

问题 I have looked at Muenchian Grouping - group within a node, not within the entire document but it is not quite working for me. The Muenchian method alone does not do it either for me. I have also looked at XSLT 1.0: grouping and removing duplicate but cannot follow it completely. I have the following XML: <?xml version="1.0" encoding="UTF-8"?> <MT_MATERIALDATA> <items item="475053"> <Recordset> <CodeBusinessUnit>99</CodeBusinessUnit> <PriceValue>250</PriceValue> </Recordset> <Recordset>

问题 I have a sample XML message which contains multiple parent node. The requirement is something like if the two parent node are same, merge the child node. Sample Input Message is <document> <party> <gtin>1000909090</gtin> <pos> <attrGroupMany name="temperatureInformation"> <row> <attr name="temperatureCode">STORAGE</attr> <attrQualMany name="temperature"> <value qual="FAH">10</value> <value qual="CC">20</value> </attrQualMany> <attrGroupMany name="temperatureStats"> <row> <attr name="StatsCode